ECompute the area bounded by the polygon A, B, C,D, E, F and the circular segment area bounded bythe curve EF and line EF.RAngle theta = As given on CarmenGPointX- ftY - ftA500500B1000600C1500110013002000АE7001800F3001000Compute the area bounded by A, B, C, D, E, Arch EF and closing on A (The whole parcel in theblue lines). Report area in Acres with 4 decimals precision.Angle theta = 44° 00' 00"

Answered: Image /qna-images/answer/fa5bf902-b95a-4680-ad89-0e8dce9b08fb.jpg

E Compute the area bounded by the polygon A, B, C, D, E, F and the circular segment area bounded by the curve EF and line EF. R Angle theta = As given on Carmen G Point X- ft Y - ft A 500 500 1000 600 C 1500 1100 1300 2000 А E 700 1800 F 300 1000 Compute the area bounded by A, B, C, D, E, Arch EF and closing on A (The whole parcel in the blue lines). Report area in Acres with 4 decimals precision. Angle theta = 44° 00' 00"

E Compute the area bounded by the polygon A, B, C, D, E, F and the circular segment area bounded by the curve EF and line EF. R Angle theta = As given on Carmen G Point X- ft Y - ft A 500 500 1000 600 C 1500 1100 1300 2000 А E 700 1800 F 300 1000 Compute the area bounded by A, B, C, D, E, Arch EF and closing on A (The whole parcel in the blue lines). Report area in Acres with 4 decimals precision. Angle theta = 44° 00' 00"

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Give right answer and please solve it quickly... (1) B.B. of line PQ is N 35° W, Find it's F.B. (ii) F.B. of line AB is 182°, Find it's B.B. (iii) R.B. of line XY is S 37° W, Find it's W.C.B. (iv) W.C.B. of line MN is 272°, Find it's R.B. (v) If F.B. of line PQ is S 17° E and F.B. of line QR is N 47° E, Find angle PQR. (vi) If F.B. of line XY is 237° and F.B. of line YZ is 320°, Find angle XYZ. (vii) If F.B. of line AB is 210° and. F.B. of line AC is 120°, Find angle
Compute GCD of the following pair of numbers: 51 and 357 11571 and 1767
A triangular lot was formed bythree straight lines. Bearing of line AB is N45Eand is 160 m long; line AC and BC is 190 mlong. Point E is 100 m from A on side ABconnects point D on side AC which dividesthe area, making area AED to be 2/5 of thewhole area. Find the distance DE. a. 120.6 m c. 99.01 mb. 109.1 m d. 88.14 m
determine Mn knowing that Es=0.005294
The side BC of a triangular lotABC is 400 m. Angle ABC is 50. A 150 m lineDE, parallel to BC, divides the lot makingarea BCED to be 50 977.80 m2.1. Determine the measure of angle A. a. 63 c. 69b. 67 d. 71 2. Determine area of triangle ABC.a. 59 319.37 m2b. 51 399.67 m2c. 53 991.67 m2d. 59 913.67 m2 3. Determine the length of the line AE.a. 124.83 m c. 148.23 mb. 142.38 m d. 134.28 m
Answers a) 0.917 b) 9.17 cm c) 1.08 N
Answers a) 0.436 b) 17.44 kPa c) 31.98 kPa d) 3.57 kN/m3
a) 0.040 m b) 0.260 m c) 0.020 m d) 0.300 m
Answer are nearly around 2237N ,0 N and and 1887N
Establish the relation linking d to AB, a, and B. Calculate d for AB-500m, a = 65, and ß= 55.
what is the elevation at station BMb a. 124.77 b. 124.13 c. 127 d. 127.45 d. 123.1
4QT is 400