E R", since the subset {||x – a|| | a E E} of Let E C R™ be non-empty. For -empty and bounded below by 0, its infimum exists and is non-negative. We defi = inf{||x – a|| | a E E}. ve that dp : Rm → [0, 0) is continuous on Rm. -

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter1: Fundamentals
Section1.5: Permutations And Inverses
Problem 5E: Let f:AA, where A is nonempty. Prove that f a has right inverse if and only if f(f1(T))=T for every...
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Let E C Rm be non-empty. For x E Rm, since the subset {||x – a|| | a E E} of R
is non-empty and bounded below by 0, its infimum exists and is non-negative. We define
de(x) = inf{||x || | a E E}.
Prove that dE : R™ → [0, ∞x) is continuous on Rm.
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Transcribed Image Text:Let E C Rm be non-empty. For x E Rm, since the subset {||x – a|| | a E E} of R is non-empty and bounded below by 0, its infimum exists and is non-negative. We define de(x) = inf{||x || | a E E}. Prove that dE : R™ → [0, ∞x) is continuous on Rm. -
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