e the ultimate consolidation settlement and the 10- year settlement of the 1.5 mx1.5 m footing carrying a 400-kN load as shown in Figure Q5(a). Also assume the laboratory consolidation characteristics of a representative sample (from the mid-plane area of the clay layer) are represented by Figure Q5 (b) and the coefficient of consolidation (Cr) of the clay was determined to be 1.0 x 10-8 m/sec. (1) Estimate the immediate settlement beneath

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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Assume that it is necessary to compute the ultimate consolidation settlement and the 10- year settlement of the 1.5 mx1.5 m footing carrying a 400-kN load as shown in Figure Q5(a). Also assume the laboratory consolidation characteristics of a representative sample (from the mid-plane area of the clay layer) are represented by Figure Q5 (b) and the coefficient of consolidation (Cr) of the clay was determined to be 1.0 x 10-8 m/sec. (1) Estimate the immediate settlement beneath the centre of the footing. Assuming the Poisson's ratio of sand and soft clay are 0.3 and 0.45, respectively. (2) Determine the ultimate consolidate settlement beneath the centre of the footing (3) Estimate the settlement 10 years after completion of the footing

Soil Type
Dry sand
CPT q. (MPa)
Es (MPa)
Es = 49.
Es = 49.
Es = 290
2.875
Wet sand
2.675
Clay
5.0
-1.0 m
Y= 16.5 kN/m3
Sandy
soil
-2.0 m
Y sat = 17.5 kN/m3
-3.5 m
Soft
Y sat = 18.0 kN/m3
clay
-6.0m
Rock
(a) Soil profile
Transcribed Image Text:Soil Type Dry sand CPT q. (MPa) Es (MPa) Es = 49. Es = 49. Es = 290 2.875 Wet sand 2.675 Clay 5.0 -1.0 m Y= 16.5 kN/m3 Sandy soil -2.0 m Y sat = 17.5 kN/m3 -3.5 m Soft Y sat = 18.0 kN/m3 clay -6.0m Rock (a) Soil profile
10
Pc= 60 kPa 100 120
p' (kPa)
1.1
1.045
1.0 -
0.93
0.9
void ratio e
(b) Laboratory consolidation curve
Figure Q5
Transcribed Image Text:10 Pc= 60 kPa 100 120 p' (kPa) 1.1 1.045 1.0 - 0.93 0.9 void ratio e (b) Laboratory consolidation curve Figure Q5
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