e2x-ydx + ey-2×dy = 0

Q: Solve d4y/dx4= 5x by variation of parameters.

A: The answer is given as follows.

Q: Solve x2(y-z) p +y2(z-x)q=z2(x-y)

A:

Q: Solve 4y'' + y' – 3y = 0, y(0) = - 4, - 4, y'(0) = 0.5 y(t) =

A: The given differential equation is second order linear homogeneous differential equatio. So firstly…

Q: Solve for x and y: 1 2 y 1 4 - 3 y

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Q: Solve. Check for extraneous solutions. √4y+3-√3y+6=0

A: The equation is given by 4y+3-3y+6 = 0 To evaluate: The solution of the equation.

Q: solve for x and y. y= 2/3x -2 y= -x + 3

A: Solution: The given two equations are

Q: y=7x - 3 y=x- 3

A: We have to solve by elimination process

Q: solve for linear equation y' = x - y

A: To solve linear differential equation.

Q: y

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Q: Solve x2(y-z) p +y2(z-x)=z2(x-y)

A: value of P given below..

Q: Solve (D - D’-1)(D - D’-2)z = e3x-y

A: Given: D-D'-1D-D'-2z=e3x-y

Q: Find the general solution af the equation, y' = x(1- y).

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Q: Solve: a3z + 4. дхду? a3z a3z 4 dx²əy əx3

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Q: Solve (3x+y-z)p+(x+y-z)q=2(z+y)

A: To solve the given equation: 3x+y-zp+x+y-zq=2z+y

Q: Solve:  2x-y + z = 7 x + y - z = -4 x + 3y - 2z = -11

A:

Q: Solve by the substitution method: x + 2y = 0, (x - 1)2 + (y - 1)2 = 5.

A: Given:  x+2y=0                                          ....1x-12+y-12=5…

Q: Using Separation of Variable, solve xy3dx + (y+1)e-xdy

A: On solving this we will get

Q: ) Verify that y=e-2x is a solution of equation x(y")3+ (y')4 – y = 0

A:

Q: Solve the non-linear equation x2 = 2y + 10 Зх — у %3D 9 y = |

A: We have givenx2 =2y +10             ⋯⋯⋯⋯(i)3x -y = 9                ..........(ii)From (ii)we get…

Q: Solve. x² +y° = 25 y² = 5-x Ay 6- 4- -> -6 -4 -2 6. -2- -6- 2.

A: The given system of equations is  x2+y2=25y2=5-x Solve the equations using the substitution method.

Q: Solve the lineaŏ evuation 2メ」+ス。 =y 1 3ス)→ 4スュ-2メ3=-3 スi+フメュー5x3ー6

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Q: az Solve (x² – y² - z²)p + (2xy) q = 2xz where p = əz II

A:

Q: Solve y′ = 2(10 - y), y(0) = 1

A: Given- y'=210-y and y0=1 To solve- The above differential equation.

Q: 2. Solve y" + 2y' – 3y = 3, y(0) = y'(0) = 1.

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Q: Solve. (If there is no solution, enter NO SOLUTION.) y  =  x2 + 4x + 4 x + 2y  =  −1…

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Q: Solve (1-x³) y' -2(1+x) y = y5/2 Bernouilli

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Q: 5. Solve y" - 3y' + 2y = 2et, y(0) = 2, y'(0) = -1

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Q: ) Solve the equation (IVP) (1 +x²) – x(1+ 2y)y' = 0 y(1) = 0 %3D

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Q: solve 2 (pedoe tydy +2d₂) ² 2 = {(2²-x²=y²2) (seds tydy + z dz/d2} z

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Q: Solve. 3. x-6x 0 0,6 b. 0,-6 a. C. -6, 6 d. 1, 6

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Q: Solve y" - y'-2y %3 Зе*, у (0) %3D0, у'(0) — -2

A:

Q: Solve for x and y. X = y = -5 -3 [ 2² ] - [ -6 - 3] x -3 6 21 8

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Q: Use the method of separation of variables to solve yu, + xu, = xyu , U(x,0) = 3e*

A: In this question, we solve the partial differential equation by using the separation of variable as…

Q: Solve  x+y=a+b  ax-by=a2-

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Q: Solve using method of undetermined coefficients: 2y" + 3y - 2y = 14x² - 4x - 11, y(0) = 0, y'(0) =…

A:

Q: Solve. (If there is no solution, enter NO SOLUTION.) x2 + 4y2  =  1 x − y  =  −1 (x,…

A: Given:

Q: Solution of 2 y" = 1+y'² is

A: The given differential equation is y''=1+y'2 ......................................... (1)

Q: (5x + 2)° yo 6x° Solve for x and y. x = y =

A:

Q: Solve. (If there is no solution, enter NO SOLUTION.) y  =  x2 − x − 10 y  =  3x + 11…

A:

Q: Solve. 2x2 - 7x - 15 = 0 3. O A. z = a = -5 2 %3D 3 O B. æ = I = 5 2' C. x = I = 5 2' O D. x = -- r…

A: Given: 2x2-7x-15=0 To find: The value of x

Q: y" + 3y' + 2y = 0 %3D

A: Given the differential equation is y" + 3y' + 2y = 0. Here the auxiliary equation is  m2 + 3m + 2 =…

Q: Solve using elimination x + y + z= 6 5x + 2y + 3z =8 6x + 3y + 8z = 10

A: The equations are given by,

Q: Solve: y′′ −6y′ +5y = e4x

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Q: Solve for x. R 3x IS 15 V U 20

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Q: Solve the IVP: y + - (1+2)*, y(1) = 6. 1+x

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Q: Solve y' %3D 4ry - 2, у(0) — 19 y(x) =

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Q: How to solve this equation y" - 4y" + 2y' - 16y = 4x + 1 using Variation of Parameters.

A: Step:-1 Given that y'''-4y''+2y'-16y=4x+1 For complementary function, The auxiliary equation is…

Q: solve     y'' - y' - 4y = e6x

A:

Q: solve y’’ + y’ – 6y = e2x – 2

A: