Eight percent of the population is infected with Herpes simplex-2 virus (HSV2). If you select four individuals at random from a population, a. What is the probability of finding exactly 3 individuals with HSV2? b. What is the probability of finding at least one HSV2-positive individual in the sample? [HINT: All possibilities include 1 person has HSV2, 2 people have HSV2, 3 people have HSV2, or 4 people have HSV2; so if you added all those together you would have a probability of 1. First find Pr(X=0), and Pr(X ≥ 1)=1- Pr(X=0).]
Eight percent of the population is infected with Herpes simplex-2 virus (HSV2). If you select four individuals at random from a population, a. What is the probability of finding exactly 3 individuals with HSV2? b. What is the probability of finding at least one HSV2-positive individual in the sample? [HINT: All possibilities include 1 person has HSV2, 2 people have HSV2, 3 people have HSV2, or 4 people have HSV2; so if you added all those together you would have a probability of 1. First find Pr(X=0), and Pr(X ≥ 1)=1- Pr(X=0).]
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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Eight percent of the population is infected with Herpes simplex-2 virus (HSV2). If you select four
individuals at random from a population,
a. What is the probability of finding exactly 3 individuals with HSV2?
b. What is the probability of finding at least one HSV2-positive individual in the sample?
[HINT: All possibilities include 1 person has HSV2, 2 people have HSV2, 3 people have HSV2, or
4 people have HSV2; so if you added all those together you would have a probability of 1. First
find Pr(X=0), and Pr(X ≥ 1)=1- Pr(X=0).]
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