Answered: emale Parent: Wild ale Parent: Wild…

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter19: Population And Community Ecology

Section: Chapter Questions

Problem 3ACQ: Figure 19.11 Age structure diagrams for rapidly growing, slow growing, and stable populations are...

See similar textbooks

Related questions

Question

Background Information:

Autosomal Dominant/Recessive
- The trait is encoded by a single genetic locus with two segregating alleles: One dominant (A) and one recessive (a). The locus is not on a sex chromosome, and is not linked to any other trait unless specified.
Autosomal Codominance
- This mode is the same as Autosomal Dominant/Recessive, except that neither allele is
dominant or recessive and heterozygous individuals have a distinct phenotype.

X-linked Dominant/Recessive

- The trait is encoded by a single genetic locus with two segregating alleles: One dominant (A) and one recessive (a). The locus is located on the X-chromosome, and is not linked to any other trait unless specified.
X-linked Codominance
- This is the same as X-linked dominant/recessive, except that heterozygous females (two
copies of the X-chromosome) experience a distinct phenotype relative to females that are homozygous for either of the two alleles. Males will be segregating with two phenotypes (because they only have one X-chromosome), and females will be segregating with three phenotypes.
Autosomal Dominant/Recessive (AA lethal)
- This mode is the same as Autosomal Dominant/Recessive, except that individuals that are homozygous for the dominant allele are embryo-lethal. Since they are embryo-lethal, they are not observed. This causes the ratio of progeny to be skewed, and it also makes it impossible to establish a true-breeding line with the dominant allele.

What to do

- Determine how many genes are responsible for the segregating traits?

- How they are inherited?

- Whether they are linked, and if they are linked, what are the map distances?

Crosses - Population Summary

- Images Attached!

Wild Population: 500 Flies (1. 500)
Female Parent: Wild
Male Parent: Wild
Bristles
Shaven
Singed
Spineless
Bristles
Shaven
Singed
Spineless
Vial 1: 417 Flies (501 - 917)
Female Parent: Fly 12 (Wild)
Male Parent:
F
Bristles
Shaven
Singed
Spineless
M Total
74
92
166
75
62 137
95 102 197
Singed
Fly 9 (Wild) Shaven
FM Total
106 83 189
106 122 228
000
Vial 2: 435 Flies (918 - 1352)
Female Parent: Fly 2 (Wild)
Male Parent: Fly 3 (Wild)
F
M Total
-
0
0 0
236 199 435
00
0
Shaven
-
- Spineless
-

Vial 3: 417 Flies (1353 - 1769)
Female Parent: Fly 4 (Wild) Spineless
Male Parent: Fly 461 (Wild) Singed
Bristles
Shaven
Singed
Spineless
Bristles
F M Total
Shaven
Singed
Spineless
000
Vial 4: 487 Flies (1770 - 2256)
Female Parent: Fly 10 (Wild)
Male Parent: Fly 79 (Wild)
F M Total
101 110 211
106 100 206
72 65 137
106 138 244
53 53 106
Singed
Singed

Expert Solution

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.

Similar questions