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equations of equilibrium, all work, and units 24 points): Determine the magnitude of force F and P. 1oolb y •FBD: F) angle cales? 100 lb QO (-3) 110° Fay 55 Ca15) 3 ఆర్భ) 4 105P F 55° You dont knon Fand P..? Pardllelogram neorrect t not needed here Calculations: Fx = Ecos Ca15°)= -54.72 lbs ? Fy -F sin cai5°)= -38,31|bs P PC415)=-89.59/bs Py3DPC315)%3D-67.2 lbs anafropridte Sin Clo5°) Sin Ca150) 66.Slbs 64.231bs= P.sin Ca15°) P= +l1.98 or ll2 ibs in Ibs Fat Fa 100 Cos CI00)= -34.20lbsv -y directi- on Fay lo0lbs sin Ca15°) = -57.35 |bs Fax+ - 가 incorrect. show E of E C-34.20 1bs) + C-57.35|bs)- F

equations of equilibrium, all work, and units 24 points): Determine the magnitude of force F and P. 1oolb y •FBD: F) angle cales? 100 lb QO (-3) 110° Fay 55 Ca15) 3 ఆర్భ) 4 105P F 55° You dont knon Fand P..? Pardllelogram neorrect t not needed here Calculations: Fx = Ecos Ca15°)= -54.72 lbs ? Fy -F sin cai5°)= -38,31|bs P PC415)=-89.59/bs Py3DPC315)%3D-67.2 lbs anafropridte Sin Clo5°) Sin Ca150) 66.Slbs 64.231bs= P.sin Ca15°) P= +l1.98 or ll2 ibs in Ibs Fat Fa 100 Cos CI00)= -34.20lbsv -y directi- on Fay lo0lbs sin Ca15°) = -57.35 |bs Fax+ - 가 incorrect. show E of E C-34.20 1bs) + C-57.35|bs)- F

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Problem (30 Points: Free body diagram 6 points; solution showing assumptions, equations of equilibrium, all work, and units 24 points): Determine the magnitude of force F and P. 1çolb y •FBD: C angle cales? 20 100 lb (-3) Fax 110° Fay 5. 3. 55° 니 1053P Parallelogram neorrect t not needed nere Cal5) o) F 55° You don't kno Fand P..? innaropridte-E= Feos Ca15°)= -54.72 l6s% •Calculations: arous %3D Fy -F sin ca15°= -38.31|bs sin Clo5°) sin Ca15°) %3D 66.Slbs P PC415)=-89.59169 64.231bs= P.sin Ca15°) Py = PC3/5) = - 67.2 lbs %3D P= +\|1,98 or ||2lbs in Ibs Fa 100 Cos C1100) = -34.201bsv -y directi- on %3D Fay 100 lbs sin Ca5°) = -57.35 bs l00|bs sin Ca15o) =-57.35 lbs %3D Fare + Fay -F Process incorrect. show E of E Solve for Fand p C-34.a0 lbs)a + C-5구.35|bs) 끼 F-66.8 lbs in neg x ty direction 3. 4.
Transcribed Image Text:Problem (30 Points: Free body diagram 6 points; solution showing assumptions, equations of equilibrium, all work, and units 24 points): Determine the magnitude of force F and P. 1çolb y •FBD: C angle cales? 20 100 lb (-3) Fax 110° Fay 5. 3. 55° 니 1053P Parallelogram neorrect t not needed nere Cal5) o) F 55° You don't kno Fand P..? innaropridte-E= Feos Ca15°)= -54.72 l6s% •Calculations: arous %3D Fy -F sin ca15°= -38.31|bs sin Clo5°) sin Ca15°) %3D 66.Slbs P PC415)=-89.59169 64.231bs= P.sin Ca15°) Py = PC3/5) = - 67.2 lbs %3D P= +\|1,98 or ||2lbs in Ibs Fa 100 Cos C1100) = -34.201bsv -y directi- on %3D Fay 100 lbs sin Ca5°) = -57.35 bs l00|bs sin Ca15o) =-57.35 lbs %3D Fare + Fay -F Process incorrect. show E of E Solve for Fand p C-34.a0 lbs)a + C-5구.35|bs) 끼 F-66.8 lbs in neg x ty direction 3. 4.
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