et A (x,y (+3ay +47 ,5 ty)2and letBfiND LAf and use it to Find A (u)la WRIT DOWN A AND, USINU THE APPROPPIATE SIMILIRATY PANSFORAMATION ONOR TAIN LA (Peminder: of Course A ILA and A-AjFivp TEACE (CA)0BTAIN CU3AvD COMPARE IT TO TPACZ (CAf')eb3FiNe(B') a twoTE IK SUch Ihat vspan(8). (PenarK he vector space spandimensional Subspace (plane) of IR

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Asked Nov 29, 2019
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Can you please answer all 5 questions clearly so its easier for me to study. Thank you very much.

et A (x,y (+3
ay +47 ,5 ty)
2
and let
B
fiND LAf and use it to Find A (u)
la WRIT DOWN A AND, USINU THE APPROPPIATE SIMILIRATY PANSFORAMATION ON
OR TAIN LA (Peminder: of Course A ILA and A-Aj
Fivp TEACE (CA)
0BTAIN CU
3
AvD COMPARE IT TO TPACZ (CAf')
eb
3
FiNe
(B') a two
TE IK SUch Ihat v
span(8). (PenarK he vector space span
dimensional Subspace (plane) of IR
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et A (x,y (+3 ay +47 ,5 ty) 2 and let B fiND LAf and use it to Find A (u) la WRIT DOWN A AND, USINU THE APPROPPIATE SIMILIRATY PANSFORAMATION ON OR TAIN LA (Peminder: of Course A ILA and A-Aj Fivp TEACE (CA) 0BTAIN CU 3 AvD COMPARE IT TO TPACZ (CAf') eb 3 FiNe (B') a two TE IK SUch Ihat v span(8). (PenarK he vector space span dimensional Subspace (plane) of IR

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Expert Answer

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Step 1

Hey, since there are multiple subparts posted, we will answer first three subparts. If you want any specific subpart to be answered then please submit that question and specify the subpart number in your message

Step 2

1.

Given that A(x.y.)= (x +3 : , 2y + 4:. 5x+y)u2
and p'0
P=0
0
A(1,0,0) (1,0,5) 10-5+51
0
A(0,1,0)= (0,21)-2 0 + 1
0
0
1
A(0,0,1) (3,4,0)-1 0 +4
0
-5 5
1
Thus, [A
-2
1
1
0
-1
4
A(u) A(1,2.3) (10,16,7) 0 0 +9 71
0
0
[A(u)](0,9,7)
help_outline

Image Transcriptionclose

Given that A(x.y.)= (x +3 : , 2y + 4:. 5x+y)u2 and p'0 P=0 0 A(1,0,0) (1,0,5) 10-5+51 0 A(0,1,0)= (0,21)-2 0 + 1 0 0 1 A(0,0,1) (3,4,0)-1 0 +4 0 -5 5 1 Thus, [A -2 1 1 0 -1 4 A(u) A(1,2.3) (10,16,7) 0 0 +9 71 0 0 [A(u)](0,9,7)

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Step 3

2.

...
0
A(1,0,0)= (1,0,5) 10 +0|1|+50
0
0
1
0
10
A(0,1,0)= (0,2,1)= 0 0+2
| 0
0
1
0
0
A (0,0,1) (3,4,0) 3 0 +4 0
0
1
1 0 5
Thus, A 0 2 1
3 4
0
help_outline

Image Transcriptionclose

0 A(1,0,0)= (1,0,5) 10 +0|1|+50 0 0 1 0 10 A(0,1,0)= (0,2,1)= 0 0+2 | 0 0 1 0 0 A (0,0,1) (3,4,0) 3 0 +4 0 0 1 1 0 5 Thus, A 0 2 1 3 4 0

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