Integration by parts EvaluateIn xdxx3А.In x12x2 Inx-4x2+ Cx3В.In x-dxx311+ C4x2-In x –2x2C.In xdxx31In xх21+ C4x2D.In x-dxIn x +2x21+ C4x2

Answered: Image /qna-images/answer/33b9f5a2-f308-4b22-8fda-e7631117572c.jpg

Answered: Evaluate In x dx x3 А. In x x3 1 In x…

Evaluate In x dx x3 А. In x x3 1 In x 2x2 1 + C 4x2 В. In x dx 1 1 x3 In x - 2x2 4x2 + C С. In x dx x3 1 In x x2 1 + C 4x2 - D. In x dx 1 In x + 2x2 1 +3 4x2+ C

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter1: Introduction To Algebra

Section1.3: Equations

Problem 10MRE

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Question

Integration by parts

Evaluate
In x
dx
x3
А.
In x
1
2x2 Inx-
4x2
+ C
x3
В.
In x
-dx
x3
1
1
+ C
4x2
-
In x –
2x2
C.
In x
dx
x3
1
In x
х2
1
+ C
4x2
D.
In x
-dx
In x +
2x2
1
+ C
4x2

With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.

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