Evaluate: ∫ sec6x tan3x dx

Q: Simplify csc(t)tan(t) to a single trig function or constant with no fractions.

A:

Q: d - tan-(6x³) dx

A: As per guideline we have to solve 1st one

Q: Evaluate / - *-dx x+5 xp-

A: We know that integral of (1/x) is lnx. To find the integral of the given function split the function…

Q: とsinx20

A: Use Variable separable method to dolve the differential equation. Basic Integrals ; →∫xndx =…

Q: dx Evaluate: 9 – x2 6,

A: folllow next step

Q: 312-3x| dx

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Q: S tan-1(bx) dx

A:

Q: dx Evaluate 24+x²

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Q: V9 - x dx

A: Given integral is: I=∫-339-x2dx

Q: date 12XY and y=l when X=-3 %3D

A:

Q: 30. y = tan 4a

A: Given function is : y=tan4x

Q: S tan?2xsec*2x dx

A: Use the trigonometric identity, sec2x=1+tan2x , while simplifying the given integral.   Use the…

Q: V9-4x? - dx

A:

Q: Snd tan Vx 2.

A: This is a case of the integration by substitution

Q: 1) tan wsec wdw 2) Ssin 5xsin 3xdx

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Q: Evaluate. + 5/x5 dx

A: Our Aim is to integrate the following integral given below:-∫3x6+5x5 dx -(i)

Q: Evaluate dx. /25 – x²

A: First of all, let x = 5 sin (u) and differentiate w.r.t x on both sides of the equation and find dx.

Q: x=7 sece;

A:

Q: Evaluate: AT -dx B. 이집 는 d 를

A: Evaluate the integral ∫0πxsinx1+cos2xdx

Q: What is the simplified value of lan- 2x= sec2x, tan 2x

A: Given:   tan2x-sec2x

Q: dx V64 - x

A: The given integral is ∫x364-x2 dx. Let t2=64-x2. This implies that  2t dt=-2x dxdx=-tx dt Substitute…

Q: Evaluate 8x2 - 5 x dx Done

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Q: Sinx COSX CSCX secx

A: Our objective is to solve the above equation.

Q: Evaluate : sec; 43 x cosec x dx

A: To evaluate the given integral

Q: Tan (690) × cos(-510)

A: To find: The value of . Formula used: Trigonometric reduction formula:

Q: Differentiate y= 2x tan(V2x (/25).

A:

Q: Evaluate  (from -6 to 6)∫(36−x^2)dx

A: Given query is to find the value of the definite integral.

Q: 28) y = tan-1 /3x

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Q: Write ∫ tan5 x dx in terms of ∫ tan3 x dx.

A: Write ∫ tan5 x dx in terms of ∫ tan3 x dx.

Q: Evaluate ∫x2ex dx.

A: Evaluate ∫x2exdx According to ILATE I - inverse function L - logarithmic function A - algebraic…

Q: Evaluate. 12 6e* dx J6

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Q: Express tanx -secx in terms hsin x aud cea x, : and sumplify

A:

Q: В- Sa secx(secx + tanx)dx

A: Given integral: ∫0π4secxsecx+tanxdx Use trignometric identity: secx=1cosx

Q: Evaluate: 2 sinxcos³xdx is equal to 0

A:

Q: Write the expression csc(arctan x/√2) in algebraic form.

A: Known fact: csctan-1x=1+x2x.

Q: fx x tan x dx

A: We can find the integration using integration by parts as below.

Q: Se -2x sin 2xdx

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Q: Simplify arcsin (-). KIO $0 11x 6 7x :|00

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Q: Write sin (x - π) in simplified form.

A: Using compound angle formula of trigonometry.

Q: Differentiate: y = tan(8x2 – 3x*)

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Q: Sketch x = 1/y.

A: Sketch.x=1y

Q: Evaluate tan° (x) sec* (x)dx in the two different ways indicated.

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Q: tan 2x dx Vcos? 2x – 25

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Q: Use the Quotient Rule to evaluate and simplify

A: Given that: ddx x - 13x + 2

Q: Differentiate. y = 10 tanπ θ

A: Given:y=10tan πθ

Q: Simplify (sec x – tan x) (csc x + 1)

A: We have to simplify the given expression…

Q: Write the expression as a power of  e.   (tanx) secx

A: Given expression is tanxsecx.

Q: |tan 3x sec 3xdx 3.

A:

Q: Evaluate [8e(* º dx

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Q: Simplify (tanx+cotx)^2

A: We can use the trigonometrical identity in order to solve the given problem.