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Evaluate the definite integral. Use the integration capabilities of a graphing utility to verify your result. 2x + 16 Step 1 2x To find the definite integral dx, apply the basic integration rule. V x + 16 Let u = x + 16. Differentiate u in terms of x, du = 2 x dx. Step 2 Rewrite the integration in terms of u. 1 du 2x x3D 3 dx = 9 + ,X A Step 3 Apply the power rule of integration. (x = 3 1 du = [x = 3 |-1/2 -1/2 du -1/2 -1/2 + 17x = 3

Evaluate the definite integral. Use the integration capabilities of a graphing utility to verify your result. 2x + 16 Step 1 2x To find the definite integral dx, apply the basic integration rule. V x + 16 Let u = x + 16. Differentiate u in terms of x, du = 2 x dx. Step 2 Rewrite the integration in terms of u. 1 du 2x x3D 3 dx = 9 + ,X A Step 3 Apply the power rule of integration. (x = 3 1 du = [x = 3 |-1/2 -1/2 du -1/2 -1/2 + 17x = 3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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-1/2 +17x = 3 or -1/2 +1 1/2 1/2 7x = 3 2. 01 Step 4 Substitute the expression for u, and obtain the integral. 1. du = 3. 2+16 0. 2(V + 16 + 16 2(VT V16) 2( – 4) %3D = 2. Submit Skip (you cannot come back) 2.
Transcribed Image Text:-1/2 +17x = 3 or -1/2 +1 1/2 1/2 7x = 3 2. 01 Step 4 Substitute the expression for u, and obtain the integral. 1. du = 3. 2+16 0. 2(V + 16 + 16 2(VT V16) 2( – 4) %3D = 2. Submit Skip (you cannot come back) 2.
Evaluate the definite integral. Use the integration capabilities of a graphing utility to verify your result. 2x dx +16 Step 1 2x To find the definite integral dx, apply the basic integration rule. x² + 16 Let u = x + 16. Differentiate u in terms of x, du = 2 2 x dx. Step 2 Rewrite the integration in terms of u. x 3 1 1 du 2x x +16 Vu Step 3 Apply the power rule of integration. X= 3 x = 3 -1/2 -1/2 du du = -1/2 -1/2 + 17x = 3
Transcribed Image Text:Evaluate the definite integral. Use the integration capabilities of a graphing utility to verify your result. 2x dx +16 Step 1 2x To find the definite integral dx, apply the basic integration rule. x² + 16 Let u = x + 16. Differentiate u in terms of x, du = 2 2 x dx. Step 2 Rewrite the integration in terms of u. x 3 1 1 du 2x x +16 Vu Step 3 Apply the power rule of integration. X= 3 x = 3 -1/2 -1/2 du du = -1/2 -1/2 + 17x = 3
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