Evaluate the in verse matriX SinX CosX 2- |-cosX sin X

Q: show that cos 6x = cos 2x (4cos2 2x-3)

A: Given,           To prove: cos 6x = cos 2x (4cos2 2x-3)

Q: Integrate using u substitution and table    cos2x/(5sin2x-sin^2(2X)^1/2

A:

Q: find sin3xsin3x

A: Given:

Q: write sin(3x)cos(6x) + cos(3x)sin(6x) as a single trig function

A: This question is related to Trigonometric identities, we will solve it using given information.

Q: Find f'co) if fco)= (Since\ %3D

A:

Q: a) Buktikan, Prove that, (sin x + cosx)* = sin 2x + 2 sin 2x +1.

A: The given equation,sinx+cosx4=sin22x+2 sin2x+1

Q: = Cosx (2

A: Using identity sin(a+b)=sin(a)cos(b)+cos(a)sin(b), we will verify the given identity

Q: Prove: sin (2 cosx) = 2x1-x

A:

Q: Prove the identity. cos²x 1+ sinx (1– sinx)? 1- sinx

A:

Q: Compute without using a calculator.

A: To evaluate: sin-1sin-5π6 Solution: We know that, sin-x=-sinx and sin-1-x=-sin-1x Evaluating the…

Q: 1 sinx # 1-cos2x ẩu! (6 2

A: Given query is to find the value of the limit.

Q: 6) 1-cosx %3D 1+cosx (cotx - cscx)2

A:

Q: Evaluate fi' sin(21*)dt

A:

Q: Verify the identity: cot2 2x + cos2 2x + sin2 2x = csc2 2x

A: The given identity is ot2 2x + cos2 2x + sin2 2x = csc2 2x

Q: Find cos θ⁡ whose terminal side passes through the point (-3,4).

A:

Q: 6. Verify the identity: sin x 1 + cosx 1 + cosx sin x 2 cscx %3D

A: Topic = Trigonometry

Q: 1. tanxsins + cosx = secx

A: using trignometric identities:-

Q: sin2x+cos2 for x = 55 degrees.

A: Apply trigonometric identity cosA=sinπ2-A to rewrite the expression. sin2x+cos2x=sin2x+sinπ2-2x…

Q: Express as a product:3 cos 2x + 3 cos 6x

A: 3cos2x+3cos6x we have to express as product

Q: Establish the identity.

A:

Q: Prove that sin3x/sinx - cos3x/cosx = 2

A:

Q: Verify the identity: [sin 2x + (sin 3x + sin x)]/[cos 2x + (cos 3x + cos x)] = tan 2x

A: Consider the identity, sin2x+sin3x+sinxcos2x+cos3x+cosx=tan2x To apply the trigonometric identity,…

Q: Integrate cosx cos (x-a)

A:

Q: (8) If fCx) = 3x*- +4X +1, Sind

A:

Q: prove tan^4x=cos4x-4cos2x+3/cos4x+4cos2x+3

A: Basic trigonometry proof

Q: Verify: 1. (sinx – cosx)² – 1 = -sin2x %3D

A: We can verify the statement as below

Q: Prove the equation sec2 x csc2 x = sec2 x + csc2 x is an identity.

A: Given equation is, sec2csc2x=sec2x+csc2x

Q: Show that sin , +sin ¤, = 2 cos[;(4, – Þ,)]sin[;(P, +Ð,)]

A:

Q: 1.) ∫(sin3x+cos2x)²dx

A: Evaluate: ∫sin3x+cos2x2dx

Q: prove that sin⁴x - sin²3x+sinx-3 = 0 has no solution.

A: prove that sin⁴x - sin²3x+sinx-3 = 0 has no solution.

Q: Show that 3(sinx-cosx)*+6(sinx + cosx)²+4 (sinºx+cos°x) = 13 %3D

A:

Q: Find the points of intersection between r =2 cos20 andr=- %3D 1- cose

A: To find the intersection point two curve we have to find r,θ by solving given curve.

Q: Verify identity cot2 2x + cos2 2x + sin2 2x = csc2 2x.

A:

Q: Express as a product.cos x + cos 2x

A: Given expression: cosx+cos2x

Q: Verify the identity: tan2 2x + sin2 2x + cos2 2x = sec2 2x

A:

Q: Verify the identity. sin 5x + sin 3x 2 cos x 4 sin x cos3 x - X – 4 sin x cos x 3.

A:

Q: Evaluate | xsin 'dx

A:

Q: prove the identity sin^2xcos^2x+cos^(4)x=(1-sinx)(1+sinx)

A:

Q: compute:   ∫sin^3xcos^2xdx

A: We have to find:

Q: Verify the identity : 2 sin2x-1= 1- 2 cos2x

A:

Q: Prove CotA= sin2A/1-cos2A

A:

Q: What is the greatest possible value for the product of 2-sinx and 3 + cos5x

A: (2-sin(x))(3 + cos(5x)) =6-3sin(x)+2cos(5x)-sin(x)cos(5x)

Q: verify the identity: (sinx + cosx)2 = 1 + 2sinxcosx

A:

Q: (cos 20+ jsin 20) (cos 60+ jsin 60)1" (cos 30+ jsin 30)°(cjs 1000)

A: the given expression is cos 2θ+jsin 2θ5cos 6θ+jsin 6θ10cos 3θ+jsin 3θ9cjs 10θ Using De Moivre's…

Q: Evaluate: cos32xdx cos³2x - +C 6. cos2x (A) cos32x +C cos2x B sin2x sin32x +C 6. = 2 sin32x + C 6.…

A: Given query is to find the integral.

Q: Integrate  cos3xcos2x

A:

Q: Verify the identity: sin2xcotx-cos2x=1

A: Given that, The identity is, sin2x cotx - cos2x = 1 we have to prove it.

Q: 1 Cosx %3D secx+1 COSx+1

A: As per our guidelines we are supposed to answer only one question.Kindly repost other question as…