Question
Asked May 11, 2019
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Evaluate the indefinite integral. Assume the integrand has domain
r 0.470588235294118
V289z2 -6-4
+ C
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Evaluate the indefinite integral. Assume the integrand has domain r 0.470588235294118 V289z2 -6-4 + C

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Expert Answer

Step 1

Firstly, we substitute 289x^2-64=t , and solve as shown on board.

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Step 2

Now, we set sqrt(t)=z and use the result that that integration of 1/(z^2+a^2) is ( 1/a )arctan (z/a) to find I1

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Step 3

Now, we substitute value of  I1 an...

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