Question

Asked May 11, 2019

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Step 1

Firstly, we substitute 289x^2-64=t , and solve as shown on board.

Step 2

Now, we set sqrt(t)=z and use the result that that integration of 1/(z^2+a^2) is ( 1/a )arctan (z/a) to find I1

Step 3

Now, we substitute value of I1 an...

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