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Evaluate the integral. 2 + du - Step 1

Evaluate the integral. 2 + du - Step 1

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.2: Remainder And Factor Theorems
Problem 51PS
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Step 2 Therefore, an antiderivative of f(u) = 2 + is 4+1 4 u 5. 9+1 3 u 10 F(u) = 2 u 5 4+1 4 9+1 10 Step 3 Since and we now have 2+u -- [2u+ - 40 4 To evaluate, we substitute 1 and 0 into the antiderivative F(u) = 2 u + u5 - u10 and subtract the 25 40 results F(1) - F(0). We calculate F(1) and F(0) as follows. 4 F(1) = 2 + 25 F(0) = 45
Transcribed Image Text:Step 2 Therefore, an antiderivative of f(u) = 2 + is 4+1 4 u 5. 9+1 3 u 10 F(u) = 2 u 5 4+1 4 9+1 10 Step 3 Since and we now have 2+u -- [2u+ - 40 4 To evaluate, we substitute 1 and 0 into the antiderivative F(u) = 2 u + u5 - u10 and subtract the 25 40 results F(1) - F(0). We calculate F(1) and F(0) as follows. 4 F(1) = 2 + 25 F(0) = 45
Evaluate the integral. du Step 1 n+1 n+1 An anti-derivative of kx", as long as n -1, is k n+1 n+1 Step 2 Therefore, an antiderivative of f(u) = 2 +u -u° is 10 4+1 4 u 9+1 F(u) = 2 u u + 4+1 4 9+1 10 Step 3 승(승)-1 and , we now have Since %3D 2 + 4
Transcribed Image Text:Evaluate the integral. du Step 1 n+1 n+1 An anti-derivative of kx", as long as n -1, is k n+1 n+1 Step 2 Therefore, an antiderivative of f(u) = 2 +u -u° is 10 4+1 4 u 9+1 F(u) = 2 u u + 4+1 4 9+1 10 Step 3 승(승)-1 and , we now have Since %3D 2 + 4
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