Evaluate the integral. |/ 5 sin-a da =| +C NOTE: Enter the exact answer in expanded form.

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A: To solve the definite integral. Ans=5

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Q: Evaluate the integral. In(x + 7) dx -6 NOTE: Enter the exact answer in expanded form.

A: The given integral,∫-66ln(x+7) dx

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A: To evaluate the definite integral from suitable geometric formula , (without using integration)

Q: Evaluate the indefinite integral.

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Q: Evaluate the integral. 10 sinx dx + C NOTE: Enter the exact answer in expanded form.

A: We will solve this integral by integration by parts.

Q: Evaluate the integral. / 5 sin-z da + C NOTE: Enter the exact answer in expanded form.

A: Given: Let I=∫5 sin-1 x dx To Find:  To evaluate the given integral.

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A: We have to solve the following integral -  (a) ∫x9-x2dx

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A: Given: ∫cosθ.sinsinθdθ for evaluating this integral, we substitute  sinθ=t now differentiate both…

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A: We have to solve the integral                                          ∫0π2cos3xsin2xdx

Q: Evaluate the integral. 6 sin" -1 dx: +C |3D NOTE: Enter the exact answer in expanded form.

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Q: 29. -4 3x/4 dx 寸

A: Substitute x/4 = t, then  dx4=dtSo,∫-113tdt4=4∫-113tdt

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A: we have to find the integral ∫x2x2+9dx algebraically using x2=x2+9-9. then we have to find the…

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A: The given integral is ∫0πsin25rdr formula used: cos2t=1-2sin2t⇒sin2t=1-cos2t2

Q: Evaluate the integral.

A: Given ∫0π2sinθ·ecosθdθ

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A: Given : ∫0π2sin11(θ)cos5(θ)dθ ∫0π2sin10(θ)sin(θ)cos5(θ)dθ∫0π2sin2(θ)5sin(θ)cos5(θ)dθwe know that…

Q: Evaluate the integral. '(v©) do sec NOTE: Enter the exact answer.

A: Use basic identities of integration.

Q: Evaluate the integral.  integral sin 6  x  dx

A: Given ∫sin6x dx We use sin2x=1-cos2x2cos2x=1+cos2x2

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A: To evaluate the given integral.

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A: Given- ∫xsinx2cos8x2 dx To find- The value of the above integral. Concept Used- The above integral…

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A: Given:∫ sin22θ cos32θ dθ

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A: The objective is to check which integral is greater.

Q: Evaluate the integral. In(x) dx NOTE: Enter the exact answer.

A: Topic  = Integration

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A: Explanation of the solution is given below...

Q: Evaluate the integrals -dp- 5. / sin? cos x

A: Since you have asked multiple questions, we will solve the first question for you .…

Q: 2(-3x+1), dx

A: I=∫ 32(-3x+1) 2-3x dx21-3x =t21-3x ln2  ddx(1-3x) dx=dt-3 ln(2) 21-3x dx=dt2-3x dx=dt-6 ln 2

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A: Given: I=∫02πsin2(13θ)dθ

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Q: Evaluate the integral. sin(0) d0

A: This question is based on the concept of definite integrals . For integrating it first we have to…

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Q: Evaluate the indefinite integral sin2 (7 - 2) de

A: Indefinite Integration

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A: The solution are next step

Q: T/2 sin & cas Ode sinte

A: