Homework Help is Here – Start Your Trial Now!
Math
Calculus
Evaluate the integral. /x² – 36 Vx2 – 36 -dx + 6cos + C Vx² – 36 -dx = Vx² – 36 – 6cos- () + C x² – 36 ()- -dx = + 6sin + C Vx2 – 36 x² – 36 -dx = Vx – 36 – 6sin + C x² – 36 dx = x² – 36 cos +C

Evaluate the integral. /x² – 36 Vx2 – 36 -dx + 6cos + C Vx² – 36 -dx = Vx² – 36 – 6cos- () + C x² – 36 ()- -dx = + 6sin + C Vx2 – 36 x² – 36 -dx = Vx – 36 – 6sin + C x² – 36 dx = x² – 36 cos +C

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.2: Remainder And Factor Theorems
Problem 51PS
See similar textbooks
icon
Related questions
Question
100%
Evaluate the integral. 36 dx = x2 – 36 + 6cos-! + C 36 dx = Vx – 36 – 6cos () +c Vx² 36 dx = + 6sin-! - C Vx – 36 Vx² – 36 dx = V? - 36 – 6sin-! + C Vx2 – 36 dx%3D Vx2 – 36 cos-
Transcribed Image Text:Evaluate the integral. 36 dx = x2 – 36 + 6cos-! + C 36 dx = Vx – 36 – 6cos () +c Vx² 36 dx = + 6sin-! - C Vx – 36 Vx² – 36 dx = V? - 36 – 6sin-! + C Vx2 – 36 dx%3D Vx2 – 36 cos-
Expert Solution
steps

Step by step

Solved in 4 steps with 5 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer