Evaluate the iterated integral. (x+y+ z) dx dz dy

Q: Evaluate the iterated integral.

A: Given, ∫12∫13lnxydydxy To evaluate above integration.

Q: Evaluate the iterated integral. 24 (x + y + z) dx dz dy of

A: To find: ∫02∫04∫01x+y+zdxdzdy

Q: Evaluate the iterated integral. 8. (++ y + z) dx dz dy

A: We will evaluate the integral one-by-one with respect to x,z and y

Q: Evaluate the iterated integral given below

A: Given integral is, ∫12∫12ydxdyx+y2. It is integrated as follows: ∫12∫12ydxdyx+y2=∫12ylny2+2-lny2+1dy

Q: Calculate the iterated integral. (x + y)? dx dy

A: The given integral is

Q: Evaluate the iterated integrals. 2 yz b. So So So xyz dx dy dz Jo 0 0

A:

Q: Evaluate the iterated integral. 30 900- y dx dy 30 900-y y dx dy = i

A:

Q: evaluate the iterated integral.

A: Evaluate: ∫-10∫-11 x+y+1 dx dy

Q: Evaluate the iterated integral. (x + y + z) dx dz dy

A:

Q: Evaluate the iterated integral. z sin(x) dy dz dx

A:

Q: Evaluate the iterated integral. (x + 5)dy dx 8 (x + 5)dy dx = i

A:

Q: Evaluate the iterated integral. 6 [[° (x + y) dy dx

A:

Q: Evaluate the iterated integral. 1*y dx dy Ry dx dy =

A: NOTE: Refresh your page if you can't see any equations. .

Q: evaluate the iterated integral.

A: Consider the integrals, ∫01∫01y1+xydxdy…

Q: Calculate the iterated integral. IT (20x - 9x?y2) dy dx

A: Here we have to evaluate I=∫02∫1320x3-9x2y2dydx

Q: Evaluate the iterated integral. 16 zy dx dy 16 Py dx dy = i

A:

Q: Evaluate the iterated integral given below

A: The given question is from the calculus and subcategory of the double integration we can solve this…

Q: Evaluate the iterated integral. (b) (2x + v)*dxcy 0 Jo

A:

Q: Evaluate the iterated integral. 19-y2 y dx dy 3 /9-y² у dx dy — i

A:

Q: Evaluate the iterated integral. Tt/4 y cos(x) dy dx

A:

Q: Evaluate the iterated integral. 10xyz dz dy dx 0 Jx

A: ∫02∫x2x∫0y10xyz dz dy dx= 10 ∫02∫x2xxy z220ydy dx= 5 ∫02∫x2xxy3dy dx= 5∫02x y44x2x= 54∫02x16x4 -…

Q: Evaluate the iterated integral. (x + y²) dx dy THERE

A:

Q: Evaluate the iterated integral. (x + y) dy dx

A: We have to solve given double integral

Q: Evaluate the triple iterated integral. xyz dx dy dz 0/

A:

Q: Evaluate the iterated integral. 21 V441-y у dx dy

A: NOTE: Refresh your page if you can't see any equations. . ..............(1)

Q: -1 (1x+y dxdydz 2 а. -2 J0

A:

Q: Evaluate the iterated integral. 3ze dy dx dz 1

A: We have to find the value from the given condition

Q: Evaluate the iterated integrals  ∫1 0  ∫1 0 dxdy

A: Given query is to find the value of the integral.

Q: Evaluate the iterated integral. - y² I. L (x + y) dx dy

A: Take integration

Q: Evaluate the iterated integrals a. (x-y)dydx b. cos y dxdy

A:

Q: Evaluate the iterated integral below. π | 1 S. S'y cos (x) dy dx 0 0

A: Here in given question we have to find value of iterated integral.

Q: evaluate the iterated integral.

A:

Q: Evaluate the iterated integral Vy exp dx dy 0.

A: ∫14∫0y exydx dy = ∫14yexy0y dy                                       = ∫14ye - 1 dy…

Q: Evaluate the iterated integral. IT (10 + 2x2 + oy?) dx dy

A:

Q: Evaluate the iterated integral. ||| x*y² + z² dx dy dz 0.

A:

Q: Evaluate the iterated integral. 1 2r y 8ry: dz dy dx

A:

Q: Evaluate the iterated integral below. 1 S. * S'y cos 0 0 y cos (x) dy dx

A: Given, ∫0π4∫01y cos(x)dy dx

Q: Calculate the iterated integral. '64 Y)dy dx

A: Given that a double integration and we solve this using general rule of integration. Here i attached…

Q: Evaluate the iterated integral. (x + y + z) dx dz dy III nowor

A:

Q: 2+ y²) dz dy

A:

Q: Calculate the iterated integral. (x + y)² dx dy

A: In the question we have to find integral of the given function.

Q: Evaluate the iterated integral. [[ (x + y) dx dy

A:

Q: evaluate the iterated integral.

A:

Q: Evaluate the iterated integral. (x + y²) dx dy J1

A:

Q: Evaluate the iterated integral. 2 (x + 7)dy dx 0. 2 (x + 7)dy dx = i

A:

Q: Calculate the iterated integral

A: The given double integral is  I=∫01∫04xy+ydx

Q: Evaluate the iterated integral. 5x (x + y²) dy dx J4x

A:

Q: Evaluate the iterated integral. V 4 - y2 (x + y) dx dy

A: