Evaluate the surface integral. Jy y ds = ²/3 (x³/² + y³/2), 0 ≤ x ≤ 5,0 ≤ y ≤ 3 S is the surface Z =

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Q: dx x√16x²-5 S=

A: Let I is the value of given integration.Therefore I=∫1x16x2-5dx

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A: The given integral is: I=∫x2-4x3dx

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Q: S dx x√16x²-5

A: Let I is the value of given integration.Therefore I=∫1x16x2-5dx

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A: A=P1+rnnt⇒A=Amount at time t⇒n=compounded period⇒r=rate of interest⇒t=time in years⇒P=initial amount

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Q: 33. f(x) = X 2 x2 - 1

A: As per guidelines we support only three subparts of the questions.kindly repost next questions

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Q: Solve for (x, y, z): 2x-2y+z=10 x+y-4z = - 17 3x-y + 2z = 13 O (4, -2, 1) O (1, -2, 4) O (2, 4, -1)

A: We have,  2x-2y+z=10 , x + y - 4z = -17 , 3x - y +2z = 13

Q: 4 3 -3 +---)-(6) --- 00 0 12 0 A-1 = 120 A-21= 0 5 3 0 0 0 3 3 -3 -(6)-( 0 -1 0 1 2 -1 1 0 0 1 0 0 0…

A: ⇒A-I=43-3000120 ⇒A-2I=33-30-1012-1 ⇒A-4I=13-30-3012-3

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