Answered: EVALUATE USING HALF-ANGLE SUBSTITUTION… | bartleby

Algebra & Trigonometry with Analytic Geometry

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter6: The Trigonometric Functions

Section6.1: Angles

Problem 27E

See similar textbooks

Related questions

Question

EVALUATE USING HALF-ANGLE SUBSTITUTION
dx
5+ 4 sin a
A. aretan
5 tan () +4
+ C
3
В. 2
5 tan () + 4
arctan
3
С. 2,
arctan
'5 tan (골z) +4
+ C
3
3
5 tan () +
1
-arctan
+C
3

Expert Solution

Step by step

Solved in 4 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

After seeing the additional solution for Fx(x,y), shouldn't it be -2sin(e2x) instead of positive 2sin(e2x) since it is Fx = 0 - sin(e2x)(2)
If from any point P on circle x^2+y^2+2gx+2fy+c=0,tangents are drawn to the circle x^2+y^2+2gx+2fy+c sin^2(alpha)+(g^2+f^2)cos^2(alpha)=0,then find the angle between the tangents.
soultions from previous is COV(x,y)=3, corraaltion = pxy=1/2,
Evaluate ∫ex cos3(ex) dx using tables after performing the substitution u = ex.
How did you get from 1+cos2x to 1+cos2x-sin2x? How did you get from 4cos(x/2) to -2(1+cosx)? How did you get from 1+cosx-since to 2cos2x?Does the tangent x cancel itself out? What does the last step say? I can’t read it
For part c: Since I already found the MLE for theta in part b, wouldn't the MLE for median be just (theta from part b) divided by square root of 2 (theorem of Invariance of MLE) = max (xi) / 2^1/2 ?
The solution of some second order linear DEQ is exp(-7x)[5sin(1x)+ 7cos(1x)] which can also be expressed as A*exp(-D*x)*sin(F*x+G). Determine A,D,F, and G (degrees).
Verify (working on one side): Cscx/ tanx + cotx = cosx
which equation is true if tan 22.5° =w/12 Equation 1: W=12 tan 22.5° Equation 2: W= tan 22.5°/12 Equation 3: W= 12/tan 22.5°
To prove cos (-u) csc (-u) tan (-u) = 1, which of the following is correct as a first step? a. cos (-u) csc (-u) tan (-u) = cos u (-csc u) (-tan u)b. cos (-u) csc (-u) tan (-u) = -cos u (csc u) (-tan u)c. cos (-u) csc (-u) tan (-u) =cos u (csc u) (tan u)d. cos (-u) csc (-u) tan (-u) = cos u (-csc u) (tan u)
Find sin θ and tan θ if the terminal side of θ lies along the line y = −8x in QII. sin θ = tan θ =
How would you rewrite this when applying the least common dominator rule for( -sin t/cos t) + (cos t/1-sin t)

SEE MORE QUESTIONS

Recommended textbooks for you

Algebra & Trigonometry with Analytic Geometry

Algebra & Trigonometry with Analytic Geometry

Algebra

ISBN:

9781133382119

Author:

Swokowski

Publisher:

Cengage

Algebra & Trigonometry with Analytic Geometry

Algebra & Trigonometry with Analytic Geometry

Algebra

ISBN:

9781133382119

Author:

Swokowski

Publisher:

Cengage

SEE MORE TEXTBOOKS