Evaluate: √x(x - 5)dx Solution: √ √x(x - 5) dx = f x²(x - 5) dx by law of exponents/ = f (x² - 5x) dx by distribution of property of equality = f x² + C₁ - 5 f x² + C₂ by Theorem 1.1 of the self-learning Module +C₁-5 + C₂ by power rule = 5 +C₁-5- Where C₁ + C₂ 5 2x² 15x² 15 3 5 2 2 3 2 + C₂ = = C 25 + C or -xz -x² + C
Evaluate: √x(x - 5)dx Solution: √ √x(x - 5) dx = f x²(x - 5) dx by law of exponents/ = f (x² - 5x) dx by distribution of property of equality = f x² + C₁ - 5 f x² + C₂ by Theorem 1.1 of the self-learning Module +C₁-5 + C₂ by power rule = 5 +C₁-5- Where C₁ + C₂ 5 2x² 15x² 15 3 5 2 2 3 2 + C₂ = = C 25 + C or -xz -x² + C
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.2: Exponential Functions
Problem 31E
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