Question

Asked Mar 16, 2019

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Evaulte the integral when x > 0

ln(x^2+17x+70)

Step 1

Integrand, I = ln(x^{2}+17x+70)

x^{2}+17x+70 can be factorised as shown below:

x^{2}+17x+70 = x^{2}+10x + 7x+70 = x(x + 10) + 7(x + 10) = (x+7)(x+10)

Step 2

Integrand, I = ln(x^{2}+17x+70) = ln[(x + 7)(x + 10)] = ln(x + 7) + ln (x + 10) since ln(AB) = lnA + lnB

Recall the famous formula of integration:

integral of ln(x) = xln(x) - x + C

Step 3

Please see the whitebaora...

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