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Ex 3: Cos2x = -6 where 2x is in 15 the second quadrant. Find the EXACT valu of cosx. V Cos2x = -6 صاف يا اب 2 cos²x-1=-6 2 cos²x = -6 +1 o/w /w/outo úlo 15 2 cos²x = -6 + 15 2 cos²x = 9 15 15 cos²x = 3 2 616 5-2 cos²x = 3 - 30 " I 42x4 TT 2 :) d TLX21 2 =) x is in the first quadrant. :: COS X = +√√30 = +√3 lo UTO

Ex 3: Cos2x = -6 where 2x is in 15 the second quadrant. Find the EXACT valu of cosx. V Cos2x = -6 صاف يا اب 2 cos²x-1=-6 2 cos²x = -6 +1 o/w /w/outo úlo 15 2 cos²x = -6 + 15 2 cos²x = 9 15 15 cos²x = 3 2 616 5-2 cos²x = 3 - 30 " I 42x4 TT 2 :) d TLX21 2 =) x is in the first quadrant. :: COS X = +√√30 = +√3 lo UTO

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.4: Values Of The Trigonometric Functions
Problem 37E
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Ex 3: Cos 2x = Cos2x = -6 the second quadrant. Find the EXACT valu of cosx. 2 cos²x-1=-6 يا رب يا رب 2 cos²x = -6 15 COSX = 2 cos²x = -6 +15 15 15 2 cos²x = 9 15 cos²x = 3 2 COSX 15 +1 cos²x = 3 lo 5-2 ភាព គ + √2/ COSXztv3, v что По -6, where 2x is in 15 = ± √√30 Halo F/J II < 2x < TT 2 TLX21 F/6 =) x is in the (4) first quadrant. :: COS X = +√30 = +√3 lo UTO
Transcribed Image Text:Ex 3: Cos 2x = Cos2x = -6 the second quadrant. Find the EXACT valu of cosx. 2 cos²x-1=-6 يا رب يا رب 2 cos²x = -6 15 COSX = 2 cos²x = -6 +15 15 15 2 cos²x = 9 15 cos²x = 3 2 COSX 15 +1 cos²x = 3 lo 5-2 ភាព គ + √2/ COSXztv3, v что По -6, where 2x is in 15 = ± √√30 Halo F/J II < 2x < TT 2 TLX21 F/6 =) x is in the (4) first quadrant. :: COS X = +√30 = +√3 lo UTO
b). Cos² (77) - Sin² (74) = Cos (2.7 48 cos (7) = IV.2 唔 12 = √√2 2 || Ex 2: Given tano = -3 4 Find cos20. Cos20 = 2 coś²³0 - 1 2 (2) ²-1 ² (13)-1 332-+ = 2 = 2 11 = 32-25 25 25 - Das 9 √2 where 3T ≤ 0 ≤ 2TT. 4 r² -3 tano = -3/1 coso = A=4 H 5 =4²+(-3)² 3. r² = 16+9 r² = 25 r = ±c
Transcribed Image Text:b). Cos² (77) - Sin² (74) = Cos (2.7 48 cos (7) = IV.2 唔 12 = √√2 2 || Ex 2: Given tano = -3 4 Find cos20. Cos20 = 2 coś²³0 - 1 2 (2) ²-1 ² (13)-1 332-+ = 2 = 2 11 = 32-25 25 25 - Das 9 √2 where 3T ≤ 0 ≤ 2TT. 4 r² -3 tano = -3/1 coso = A=4 H 5 =4²+(-3)² 3. r² = 16+9 r² = 25 r = ±c
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