Ex: You work for a company who is in charge of running power line t aland 18km offshore from a station 11km down shore. The cost for running a power line over land is $700km and $2500km for running under water. Where should be located in order to minimize cost? -11km -11-x=P 78 y? =√77324 •point where the line transfers from land to water Let be the distance between the point on the shore closest to the island and the paint the Powerline switches from land to water, in km, 06X211 Let C be the cast, ins, C70 C(x) = 700 (11-x) +2500 (√77+324) C'(x) = -700 + 2500 (& (x²+324) *. (27) =-700 + 2500x 700-2500x √77+324 √73324 700 (324)=2500x √x²+32425x 7 x²+324 = 625x² 49 49x+15876-62572 15876 = 576x2 15876= = x 576 =x FDT Intervall C'(x) soln Tab 사람 x- 17241 - mn! + 201 Q should be located 5.25 km from the closest Point on the shore to the Island
Ex: You work for a company who is in charge of running power line t aland 18km offshore from a station 11km down shore. The cost for running a power line over land is $700km and $2500km for running under water. Where should be located in order to minimize cost? -11km -11-x=P 78 y? =√77324 •point where the line transfers from land to water Let be the distance between the point on the shore closest to the island and the paint the Powerline switches from land to water, in km, 06X211 Let C be the cast, ins, C70 C(x) = 700 (11-x) +2500 (√77+324) C'(x) = -700 + 2500 (& (x²+324) *. (27) =-700 + 2500x 700-2500x √77+324 √73324 700 (324)=2500x √x²+32425x 7 x²+324 = 625x² 49 49x+15876-62572 15876 = 576x2 15876= = x 576 =x FDT Intervall C'(x) soln Tab 사람 x- 17241 - mn! + 201 Q should be located 5.25 km from the closest Point on the shore to the Island
Chapter9: Quadratic Equations And Functions
Section9.6: Graph Quadratic Functions Using Properties
Problem 287E: In the following exercises, solve. Round answers to the nearest tenth. 287. A land owner is planning...
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Car A is 80km east of Car B and begins moving west at 40km/h. At the same moment, Car B begins to move north at 70km/h. What is the closest distance in km, the cars will be from each other AND at what time t, in hours, will that distance occur?
(This is a calculus optimization problem so please show all work and include the chart of the first derivative test JUST LIKE THE EXAMPLE I AM SHOWING YOU) do it on paper pls and double check answer
Transcribed Image Text:Ex: You work for a company who is in charge of running power line t aland 18km offshore
from a station 11km down shore. The cost for running a power line over land is $700km and
$2500km for running under water. Where should be located in order to minimize cost?
-11km
-11-x=P
78
y? =√77324
•point where the line
transfers from land to water
Let be the distance
between the point on the
shore closest to the
island and the paint the
Powerline switches from
land to water, in km,
06X211
Let C be the cast, ins, C70
C(x) = 700 (11-x) +2500 (√77+324)
C'(x) = -700 + 2500 (& (x²+324) *. (27)
=-700 + 2500x
700-2500x
√77+324
√73324
700 (324)=2500x
√x²+32425x
7
x²+324 = 625x²
49
49x+15876-62572
15876 = 576x2
15876= = x
576
=x
FDT
Intervall C'(x) soln Tab
사람
x-
17241
-
mn!
+ 201
Q should be located
5.25 km from the closest
Point on the shore to the
Island
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