Exact Differentail Equation M (x,y) dx + N (x,y) dy = 0 is an Exact DE when ∂M/∂y = ∂N/∂x Solution steps Method II a. Same as in ia. b. Differentiate F with respect to y, x as constant; then equate to N.                      dF/dy = d/dy[∫M dx] + dg(y)/dy = N c. Solve for g(y) d. Substitute g(y) into F equation in (a) to get the General Solution.   Solve the following equations for exactness, then solve:

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