EXAMPLE 0.6 If A and B are as in Example 0.5, A × B × A = {(1, x, 1), (1, x, 2), (1, y, 1), (1, y, 2), (1, z, 1), (1, z, 2), (2, x, 1), (2, x, 2), (2, y, 1), (2, y, 2), (2, z, 1), (2, z, 2)}. If we have the Cartesian product of a set with itself, we use the shorthand k AxAxx A = Ak.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.9: Properties Of Determinants
Problem 40E
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Can you please help me with these two figures can you do this step by step and can explain it as well.

can you show the calculations step by step if they are any.

EXAMPLE 0.6
If A and B are as in Example 0.5,
A × B × A = {(1, x, 1), (1, x, 2), (1, y, 1), (1, y, 2), (1, z, 1), (1, z, 2),
(2, x, 1), (2, x, 2), (2, y, 1), (2, y, 2), (2, z, 1), (2, z, 2)}.
If we have the Cartesian product of a set with itself, we use the shorthand
k
AxAxxA = Ak.
Transcribed Image Text:EXAMPLE 0.6 If A and B are as in Example 0.5, A × B × A = {(1, x, 1), (1, x, 2), (1, y, 1), (1, y, 2), (1, z, 1), (1, z, 2), (2, x, 1), (2, x, 2), (2, y, 1), (2, y, 2), (2, z, 1), (2, z, 2)}. If we have the Cartesian product of a set with itself, we use the shorthand k AxAxxA = Ak.
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