Example 17.2 The deviation of the size of an item from the midpoint of the tolerance field of width 2d equals the sum of two random variables X and Y with probability densities and f(x) p(y): 1 exp x² {-2003) 20² exp {-23). 0,√2T Determine the (conditional) probability density of the random variable X for the nondefective items if the distribution p(y) does not depend on the value assumed by X.
Example 17.2 The deviation of the size of an item from the midpoint of the tolerance field of width 2d equals the sum of two random variables X and Y with probability densities and f(x) p(y): 1 exp x² {-2003) 20² exp {-23). 0,√2T Determine the (conditional) probability density of the random variable X for the nondefective items if the distribution p(y) does not depend on the value assumed by X.
Chapter6: Exponential And Logarithmic Functions
Section6.8: Fitting Exponential Models To Data
Problem 56SE: Recall that the general form of a logistic equation for a population is given by P(t)=c1+aebt , such...
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Transcribed Image Text:Example 17.2 The deviation of the size of an item from the midpoint of
the tolerance field of width 2d equals the sum of two random variables X and Y
with probability densities
and
f(x)
❤(y)
=
=
1
0x V/Z #7 CXP { - 12/0
exp
x²
20²
√2TT
√/2= exp{-2013) ·
20²
Determine the (conditional) probability density of the random variable X
for the nondefective items if the distribution p(y) does not depend on the value
assumed by X.
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