Example 2.8 The PMF of the number N of customers that arrive at a local li- brary within a one-hour interval is defined by Sn PN(n)= n! n = 0, 1,... 0 otherwise What is the probability that at most two customers arrive at the library within one hour?
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- Repeat Example 5 when microphone A receives the sound 4 seconds before microphone B.3.) Suppose X has probability generating function GX(t) = 0.2 + 0.3t + 0.1t2 + 0.4t3. What is P(X = 2)? What is P(X = 0)?This is a poisson mass function for the future lifetime of a newborn: f0(k) = λk e- λ/k! for all k>= 0,where k is a discrete random variable.For λ= 4.5 estimate e05 - the expectation of the complete future lifetime of (5)
- 1.9.5. Let a random variable $X$ of the continuous type have a pdf $f(x)$ whose graph is symmetric with respect to $x=c .$ If the mean value of $X$ exists, show that $E(X)=c$Hint: Show that $E(X-c)$ equals zero by writing $E(X-c)$ as the sum of two integrals: one from $-\infty$ to $c$ and the other from $c$ to $\infty .$ In the first, let $y=c-x$ and, in the second, $z=x-c .$ Finally, use the symmetry condition $f(c-y)=f(c+y)$ in the first.Let X1,X2,... be a sequence of identically distributed random variables with E|X1|<∞ and let Yn = n−1max1≤i≤n|Xi|. Show that limnE(Yn) = 0LetX1,X2,...,Xn be a sequence of independent and identically distributed random variables having the Exponential(λ) distribution,λ >0, fXi(x) ={λe−λx, x >0 0, otherwise (a) Show that the moment generating function mX(s) :=E(esX) =λ/(λ−s) for s< λ;
- Let x~ possion(alpha). Show that E[x(x-1)(x-2)....(x-k)]=ak+1Consider a study using a between-groups design with between-groups df = 3 and within-groups df = 4. Given an F ratio of 6.8, the researcher should: a. reject the null hypothesis if alpha is .05 but fail to reject if alpha of .01 b. reject the null hypothesis if alpha is .01 but fail to reject if alpha of .05 c. reject the null for both alpha = .01 or alpha = .05 d. fail to reject the null hypothesis whether alpha is .01 or .05Everyday, James reverses his car from his driveway on to the road in such a way that there is a very small probability P that his car will be involved in a collision. ( i) Show that the probability that there will be no collision in a five-day week is (1−P)^5 and state one assumption that is made in your answer. (iii) Let P = 0.001. Check that the Poisson approximation can be used, and find the approximate probability that James will avoid a collision in 500 days.
- Let i_t denote the effective annual return achieved on an equity fund achieved between time (t -1) and time t. Annual log-returns on the fund, denoted by In(1 + i_t) , are assumed to form a series of independent and identically distributed Normal random variables with parameters u = 6% and o = 14%.An investor has a liability of £10,000 payable at time 15. Calculate the amount of money that should be invested now so that the probability that the investor will be unable to meet the liability as it falls due is only 5%. Using only formulas, no tablesIf n is 30 and p is 0.04. using the Poisson approximation to the Binomial, the P(X < 2) is equal to a 0.4101 b. 0 .2103 C 0.0867 d. 0 .8795Find the P - value if the t-stat= -1.8, N=26, df = N-1, alpha = 0.05; and Ho: Mu1= Mu2; Ha : Mu1> Mu2 - 0.08 - 0.05 - 0.04 - 0.025