How did they compute these encircled value, formula is enough, I just need to know it. Thanks! Please include symbol and units. Thanks! EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of230 volta. Assuming negligible loeses and unity power factor, caloulate:(a) the ae input voltage between rings; (b) the full-load d-a output;(e) the full-load ae input per line.SolutionE. - 0.612 x 230 141 voltaP 25,000230I, - 0.943 X 108.7 - 102.3 amp(a)In108.7 amp(e)BAMPLI 4. A 1,500-kw six-phase synchronous converter has a full-load d-e voltage of 600. Determine: (a) the a-o voltago between rings;(®) the d-o output; (c) the a-o input per line.SolutionE. = 0.354 X 600 = 212.4 volta1,500,000Bu600(6)I. =2,500 amp(c)I- 0.472 X 2,500 = 1,180 ampEXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converteroperates at full load at an efficiency of 96 per oent and a power factor of0.95. Calculate: (a) the a-c voltage between rings; (b) the d-e output;(e) \the alternating current in each of the 12 wires.Solution(a) E. - 0.182 x 1,200 - 218.4 volta5,000,0001,200(6) Ia -4,167 amp(c) I. (efficiency = 100 per cent and power factor = 1)0.236 × 4,167 - 984 ampIn (efficiency = 96 per cent and power factor - 0.95)9840.96 X 0.95- 1,080 amp

Example 3) number of phases, m=3 power factor, pf =1 negligible loss hence efficiency, η =100 %=1…

EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of 230 volta. Asuming negligible loeses and unity power factor, caloulate: (@) the ae input voltage between rings; (b) the full-load d-a output; (e) the full-load a-e input per line. Solution ' (a) E. - 0.612 x 230 = 141 volta %3D P 25,000 230 I. - 106.7 amp I. - 0.943 X 108.7 - 102.3 amp EAMPLI 4. A 1,500-kw six-phase synchronous converter has a full- lond d-e valtage of 600. Determine: (a) the ao voltage between rings; (4) the d-o output; (c) the a-o input per line. Solution (a) B. - 0.354 X 600 - 212.4 volta P 1,500,000 600 2,500 amp (6) (e) I.- 0.472 X 2,500 - 1,180 amp EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter operates at full load at an efficiency of 96 per oent and a power factor of 0.95. Calculate: (a) the a-c voltage between rings; (b) the d-c output; (c) the alternating current in each of the 12 wires. Solution (a) E. - 0.182 × 1,200 - 218.4 volta 5,000,000 1,200 (6) la - 4,167 amp (c) I. (efficiency - 100 per cent and power factor 1) 0.236 X 4,167 - 984 amp In (efficiency = 96 per cent and power factor - 0.95) 984 0,96 X 0.95 - 1,080 amp

EXAMPLE 3. A 25-kw three-phase oonverter has a d-o output voltage of 230 volta. Asuming negligible loeses and unity power factor, caloulate: (@) the ae input voltage between rings; (b) the full-load d-a output; (e) the full-load a-e input per line. Solution ' (a) E. - 0.612 x 230 = 141 volta %3D P 25,000 230 I. - 106.7 amp I. - 0.943 X 108.7 - 102.3 amp EAMPLI 4. A 1,500-kw six-phase synchronous converter has a full- lond d-e valtage of 600. Determine: (a) the ao voltage between rings; (4) the d-o output; (c) the a-o input per line. Solution (a) B. - 0.354 X 600 - 212.4 volta P 1,500,000 600 2,500 amp (6) (e) I.- 0.472 X 2,500 - 1,180 amp EXAMPLE 5. A 5,000-kw 1,200-volt 12-phase synohronous converter operates at full load at an efficiency of 96 per oent and a power factor of 0.95. Calculate: (a) the a-c voltage between rings; (b) the d-c output; (c) the alternating current in each of the 12 wires. Solution (a) E. - 0.182 × 1,200 - 218.4 volta 5,000,000 1,200 (6) la - 4,167 amp (c) I. (efficiency - 100 per cent and power factor 1) 0.236 X 4,167 - 984 amp In (efficiency = 96 per cent and power factor - 0.95) 984 0,96 X 0.95 - 1,080 amp

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.59P

See similar textbooks

Similar questions

Characteristics of 165 kV, 150 MVA, 50 Hz 3-phase 100 km transmission linevalues are given below. r=0.103ohm/ kmx=0.525ohm/ kmy=3.3x10^-6 S/ km (a) Calculate the constants A and B for the equivalent circuit of this transmission line,(b) Load lagging power factor of 0.9 when the line is running at nominal (tag) value.if so, find the production side voltage. lesson: Power system analyses
The length of a power transmission line is ℓ = 150 km, the unit effective resistance of the line is r = 0.06 Ω/km, x = 0.4 Ω/km and the admittance value of the line is y = j4.10-6 Siemens/km. The end-of-line voltage is 154 kV, the line-head voltage is 170∠10o kV. a) The characteristic impedance of the line b) The power drawn by the load according to the given values c) Calculate the maximum power that the line can transmit?
Consider the microgrid of Figure 3.66. A three-phase transformer, T1, israted at 500 kVA, 220 VY grounded/440 V delta, a transformerwith a reactance of 3.5%.Themicrogridis supplied from anAC bus of a PV generating station.The DC bus rated at 540 V.The distributionlineis 10mileslong and has a series impedance of 0.1 + j1.0 Ω per mile and local load of 100 kVA at 440 V. The microgrid is connected to the local power grid using a three-phase transformer T2, rated at 440 V Y grounded/13.2 kV delta,500 kVA with a reactance of 8%. Compute the per unitimpedance diagram of the microgrid system. Assume the voltage base of 13.2 kV on the local power grid side and kVA base of 500
Derive conditions for economics dispatch when generating stations are connected in parallel
The area of an interconnected power system has two units operating on economic dispatch. The variable operating costs of these units are given by C =8P +0.009P2 11 1(R/h) and C = 10P + 0.008P2 where P1 and P2 are in MW. The transmission losses for the area are given by ? = 1.5 × 10−4?2 + 2 × 10−5? ? + 3 × 10−5?2 , MW ?1122 2 2 2 (R/h,) Determine the following when the area λ = 16.00 R/MWh: a. The output of each unit b. Total transmission losses c. Total load demand d. Total operating cost
A three-phase transmission line receiving end voltage is rated at 21 kV. A load of 1500 KW is connected at the receiving end of the transmission line 70 km long. The parameters of the transmission line are given by r = 0.09 Ω/km and x = 0.8 Ω/km. If the machine is working at 0.65 power factor lagging. Determine a) The series reactance of the transmission line b) Sending end line voltage c) Percentage Voltage regulation d) Percentage Efficiency
One advantage of balanced three-phase systems over separate singlephase systems is reduced capital and operating costs of transmission and distribution. (a) True (b) False
a) You have been employed as an electrical engineer by a power transmission company to design a short transmission line to supply power to a light-industrial load consumer with power system specification as follows, a 3-ph, 60Hz overhead short transmission line with a line-to-line voltage of 23KV at the load end, line impedance of 2.48 ±j6.57Ω/phase, the industry has a cumulative consumption of 9MW with a power factor of 0.85 of lagging as a result of several induction motor on its production lines.As part of the regulations for connections to the grid, you are to provide justifications and values to the Energy Commission of Ghana.(i) What would be value of the voltage between the live conductor and the neutral, between live and live voltages at the industrial premises of the factory?(ii) What load angle would expect the factory to be operating at?
A three-phase 138-kV transmission line is connected to a 49-MW load at a 0.85 lagging power factor. The line constants of the 52-mi-long line are Z = 95∠78° Ω and Y = 0.001∠90° S. Using nominal-T circuit representation, (i) Calculate the A, B, C, and D constants of the line, (ii) send end voltage
Which of the following is source of interharmonics?Induction FurnaceCycloconverterPWM inverterAll option
L-L (line) voltage of the 3-phase 50 Hz 70 km transmission line is 230 kV on the receiver (demand) side, its total impedance is R = 1 Ω / phase, L = 90 mH / phase. On the demand side, the load is powered by 80 MW power and 0.85 lagging power factor. a. Calculate the line-neutral (L-N) and line-line (L-L) voltages on the production side. b. Calculate the regulation as a percentage c. Calculate the efficiency.
Explain the importance of power system modeling and simulation in planning and managing complex power networks.