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Example 3.3. Plastic covers for CDs. Measurements for the length and width of a rectangular plastic covers for CDs are rounded to the nearest mm. Let X denote the length and Y denote the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16 mm. There are 6 possible pairs (X,Y). The probability for each pair is shown in the table below. X=129 X=130 X=131 Y=15 0.12 0.42 0.06 Y=16 0.08 0.28 0.04 1. Show the conditional conditional distribution of Y given that X = r.

Example 3.3. Plastic covers for CDs. Measurements for the length and width of a rectangular plastic covers for CDs are rounded to the nearest mm. Let X denote the length and Y denote the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16 mm. There are 6 possible pairs (X,Y). The probability for each pair is shown in the table below. X=129 X=130 X=131 Y=15 0.12 0.42 0.06 Y=16 0.08 0.28 0.04 1. Show the conditional conditional distribution of Y given that X = r.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 30E
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Example 3.3. Plastic covers for CDs. Measurements for the length and width of a rectangular plastic covers for CDs are rounded to the nearest mm. Let X denote the length and Y denote the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16 mm. There are 6 possible pairs (X, Y). The probability for each pair is shown in the table below. X=129 X=130 X=131 0.06 Y=15 0.12 0.42 Y=16 0.08 0.28 0.04 1. Show the conditional conditional distribution of Y given that X = r.
Transcribed Image Text:Example 3.3. Plastic covers for CDs. Measurements for the length and width of a rectangular plastic covers for CDs are rounded to the nearest mm. Let X denote the length and Y denote the width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16 mm. There are 6 possible pairs (X, Y). The probability for each pair is shown in the table below. X=129 X=130 X=131 0.06 Y=15 0.12 0.42 Y=16 0.08 0.28 0.04 1. Show the conditional conditional distribution of Y given that X = r.
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