EXAMPLE 4 If an object moves in a straight line with position function s f(t), then the average velocity between t a and t = b is f(b)-f(a) b-a and the velocity at t = c is f'(c). Thus the Mean Value Theorem tells us that at some time t = c between a and b the instantaneous velocity f'(c) is equal to the average velocity. For instance, if a car traveled 500 km in 5 hours, X km/h at least once. then the speedometer must have read In general, the Mean Value Theorem can be interpreted as saying that there is a number at which the instantaneous rate of change is equal to the average rate of change over an interval EXAMPLE 5 Suppose that f(0) = -2 and f'(x) s 4 for all values of x. How large can f(3) possibly be? SOLUTION We are given that fis differentiable (and therefore continuous) everywhere. In particular, we can apply the Mean Value Theorem on the interval 0, 31. There exists a number c such that f'(c) (3) - го) So f'(c) f(3) f(0) f'(c) = -2 We are given that f'(x) s 4 for all x, so in particular we know that f'(c) s Multiplying both sides of this inequality by 3, we have 3f'(c) So f(3) 2 f'(c) -2 The largest possible value for f(3) is
EXAMPLE 4 If an object moves in a straight line with position function s f(t), then the average velocity between t a and t = b is f(b)-f(a) b-a and the velocity at t = c is f'(c). Thus the Mean Value Theorem tells us that at some time t = c between a and b the instantaneous velocity f'(c) is equal to the average velocity. For instance, if a car traveled 500 km in 5 hours, X km/h at least once. then the speedometer must have read In general, the Mean Value Theorem can be interpreted as saying that there is a number at which the instantaneous rate of change is equal to the average rate of change over an interval EXAMPLE 5 Suppose that f(0) = -2 and f'(x) s 4 for all values of x. How large can f(3) possibly be? SOLUTION We are given that fis differentiable (and therefore continuous) everywhere. In particular, we can apply the Mean Value Theorem on the interval 0, 31. There exists a number c such that f'(c) (3) - го) So f'(c) f(3) f(0) f'(c) = -2 We are given that f'(x) s 4 for all x, so in particular we know that f'(c) s Multiplying both sides of this inequality by 3, we have 3f'(c) So f(3) 2 f'(c) -2 The largest possible value for f(3) is
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter5: A Survey Of Other Common Functions
Section5.4: Combining And Decomposing Functions
Problem 14E: Decay of Litter Litter such as leaves falls to the forest floor, where the action of insects and...
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