EXAMPLE 5 Find an equation of the tangent line to the parabola y=x²- 8x +9 at the point (2, -3). SOLUTION From the previous example, we know the derivative of f(x)=x²-3x+9 at the number a is f'(a) = 2a-8. Therefore the slope of the tangent line at (2, -3) is F'(2) = 2(2) - 8 = Thus an equation of the tangent line, shown in the figure, is y- y= or

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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EXAMPLE 5 Find an equation of the tangent line to the parabola y=x²-8x + 9 at the point
(2, -3).
SOLUTION From the previous example, we know the derivative of f(x) = x² - 8x + 9 at the
number a is f'(a) = 2a - 8. Therefore the slope of the tangent line at (2, -3) is
f'(2) = 2(2) - 8 =
Thus an equation of the tangent line, shown in the figure, is
y-([
y =
or
Transcribed Image Text:N 2 EXAMPLE 5 Find an equation of the tangent line to the parabola y=x²-8x + 9 at the point (2, -3). SOLUTION From the previous example, we know the derivative of f(x) = x² - 8x + 9 at the number a is f'(a) = 2a - 8. Therefore the slope of the tangent line at (2, -3) is f'(2) = 2(2) - 8 = Thus an equation of the tangent line, shown in the figure, is y-([ y = or
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