Example 7.4. Using Newton's backward difference formula, construct an interpolating polynomial of degree 3 for the data : f(-0.75) = -0.0718125, f(-0.5) = -0.02475, f(-0.25) = 0.3349375, f(0) = 1.10100. Hence find f(-1/3). 718125, f(-0.5) (Anna, B.Tech., 2003)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.6: Variation
Problem 2E
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Example 7.4. Using Newton's backward difference formula, construct an interpolating
polynomial of degree 3 for the data : f(-0.75) = -0.0718125, f(-0.5) = -0.02475, f(-0.25)
0.5) -
= 0.3349375, f(0) = 1.10100. Hence find f(-1/3).
(Anna, B.Tech., 2003)
Transcribed Image Text:Example 7.4. Using Newton's backward difference formula, construct an interpolating polynomial of degree 3 for the data : f(-0.75) = -0.0718125, f(-0.5) = -0.02475, f(-0.25) 0.5) - = 0.3349375, f(0) = 1.10100. Hence find f(-1/3). (Anna, B.Tech., 2003)
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