Example 8: Find the solution of ÿ – 4ỷ – 12y = xe4* Sol: The chr. Eq. is r² – 4r – 12 = 0 (r – 6)(r + 2) = 0 → r, = 6,r, = -2 %3D y = c¿e"1* + c2e*2* yc = c,e6x + Cze¯2x %3D yp = (Ax + B)e4* ўр — Ае4х + 4(Ах + B)e4x ÿp = 4Ae4x + 4Ae*x + 16(Ax + B)e4x -12A=1, A=-1/10 , Jaleoxe4x 4A-12B=0, Jales e4* ,B=-1/36 ур — 36 e*(3x + 1)

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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Please explain how we got number.-1/36
Example 8: Find the solution of ỹ – 4ỷ – 12y = xe4x
Sol:
The chr. Eq. is r² – 4r – 12 = 0
(r – 6)(r + 2) = 0 → rị = 6,r2 = -2
%3D
y = cqe"1* + c2e"2*
yc = c¿e6x + Cze¯2x
yp = (Ax + B)e 4*
||
ўр %—D Ае4х + 4(Ах + B)e4x
ÿp = 4Ae4x + 4Ae4x + 16(Ax + B)e4*
-12A=1, A=-1/10 , Jolesxe4*
4A-12B=0, Jales e 4x ,B=-1/36
ур
(3х + 1)
36
?
Transcribed Image Text:Example 8: Find the solution of ỹ – 4ỷ – 12y = xe4x Sol: The chr. Eq. is r² – 4r – 12 = 0 (r – 6)(r + 2) = 0 → rị = 6,r2 = -2 %3D y = cqe"1* + c2e"2* yc = c¿e6x + Cze¯2x yp = (Ax + B)e 4* || ўр %—D Ае4х + 4(Ах + B)e4x ÿp = 4Ae4x + 4Ae4x + 16(Ax + B)e4* -12A=1, A=-1/10 , Jolesxe4* 4A-12B=0, Jales e 4x ,B=-1/36 ур (3х + 1) 36 ?
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