Question
Asked Sep 19, 2019

please help with letter c. i am having trouble drawing the graph. i know there is supposed to be a vertical asymptote at y=0  but im not sure how that will impact what the rest of the graph looks like 

Example
a. Find the values of x in the interval (-4, 4) at which g is not continuous
b. Find the values of x in the interval (-4, 4) at which g is not differentiable.
c. Sketch a graph of the derivative of g.
y g(x)
+
+
х
-4 -3 -2 -1
2
3
4
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Example a. Find the values of x in the interval (-4, 4) at which g is not continuous b. Find the values of x in the interval (-4, 4) at which g is not differentiable. c. Sketch a graph of the derivative of g. y g(x) + + х -4 -3 -2 -1 2 3 4

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Expert Answer

Step 1

As the derivative of any function is the slope of that function at any point

Step 2

Slope of the g(x) is zero when

х е(-4,-2)
So, from x E (-4, -2) the graph is y = c
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х е(-4,-2) So, from x E (-4, -2) the graph is y = c

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Step 3

And graph  has a negativ...

xe(-2,0)(2,4)
So, the graph of g (x) is a line having negative slope when x e(-2,0)U(2,4)
And g (x) has positive constant slope when x E (0, 2)
So, the graph of g (x) is a line having positive slope when xe(0,2)
help_outline

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xe(-2,0)(2,4) So, the graph of g (x) is a line having negative slope when x e(-2,0)U(2,4) And g (x) has positive constant slope when x E (0, 2) So, the graph of g (x) is a line having positive slope when xe(0,2)

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Math

Calculus