Explain the determine Example BConsider the two linearly independent functions(2) – 3k.Y = 1, Yk(1)(4.96)A second-order equation having these solutions is3k1 3k+13k+2Yk1Ук11Yk+13kYk+113= 0,(4.97)Yk+21Yk+21orУк+2 — 4ук+1 + 3уk= 0.(4.98)

Name: Explain the determine Example BConsider the two linearly independent f
Uploaded: 2024-03-20T06:47:08.000Z
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Description: Explain the determine Example BConsider the two linearly independent functions(2) – 3k.Y = 1, Yk(1)(4.96)A second-order equation having these solutions is3k1 3k+13k+2Yk1Ук11Yk+13kYk+113= 0,(4.97)Yk+21Yk+21orУк+2 — 4ук+1 + 3уk= 0.(4.98)

Only solve the given determinant which equals to zero .

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Example B Consider the two linearly independent functions (1) (2) Y = 1, y = 3k. A second-order equation having these solutions is (4.96) 3k 1 3k+1 1 3k+2 Ук 1 1 1 3k Yk+1 Yk 1 Yk+1 3 0, (4.97) Yk+2 Yk+2 1 9. or Yk+2 – 4yk+1 +3yk 0. (4.98)