Exercise 1 To practice this skill, the code below samples 100 times from the population of values 0,1 and adds up the results to create a new random variable S=sum of all sample valued. Reduce the code below to three lines by removing the use of the intermediate variable x Code Start Over 1 values-c(0,1) 2 x-sample(values, 100, replace-TRUE) phat-sun(x--"0)/100 Run Code Exercise 2 After you understand the above reduction, the next step is to wrap this random variable calculation inside the replicate function and repeat the result of this calculation some large number of times N. The basic format of this function is as follows: replicate(N, random variable calculation) The code below performs N= 5 replicates of the random variable which calculates p in n 10 tosses of a fair coin and prints the result. Alter the code so that it performs N= 10 replicates of the random variable p, but with only = 5 tosses of a fair coin. Code Start Over 1 values-c("H","T") 2 phat-replicate(5, sum(sample(values, 10, replace-TRUE)--"H")/10) 3 print (phat) Run Code

Exercise 1 To practice this skill, the code below samples 100 times from the population of values 0,1 and adds up the results to create a new random variable S=sum of all sample valued. Reduce the code below to three lines by removing the use of the intermediate variable x Code Start Over 1 values-c(0,1) 2 x-sample(values, 100, replace-TRUE) phat-sun(x--"0)/100 Run Code Exercise 2 After you understand the above reduction, the next step is to wrap this random variable calculation inside the replicate function and repeat the result of this calculation some large number of times N. The basic format of this function is as follows: replicate(N, random variable calculation) The code below performs N= 5 replicates of the random variable which calculates p in n 10 tosses of a fair coin and prints the result. Alter the code so that it performs N= 10 replicates of the random variable p, but with only = 5 tosses of a fair coin. Code Start Over 1 values-c("H","T") 2 phat-replicate(5, sum(sample(values, 10, replace-TRUE)--"H")/10) 3 print (phat) Run Code

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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i need answer of all. if any answer will be skipped, your answer will be rejected. only complete answer will be accepted. b) Make a truth table for the statement ¬P ∧ (Q → P). What can youconclude about P and Q if you know the statement is true? a) Make a truth table for the statement (P ∨ Q) → (P ∧ Q). c) Make a truth table for the statement ¬P → (Q ∧ R).
import numpy as np import random n = 10 X = np.random.randint(1, 20, n*n).reshape(n,n) Y = np.random.randint(1, 20, n*n).reshape(n,n) result = np.zeros(X. shape) for i in range (len(X)): for j in range (len(Y[0])): for k in range (len (Y)): result[i][j] += X[i][k] * Y[k][j] result= result.reshape(-1,1) a = 0 for r in result: a = a + r sum_value = a[0] print("Total sum of all elements is {}".format(sum_value)) Complete analysis of this code and Big O
Give me the correct answer don't copy from others otherwise I'll give you downvotes sure
List pressure_data contains integers read from input, representing data samples from an experiment. Initialize variable sum_passed with 0. Then, for each element in pressure_data that is both at an odd-numbered index and greater than 65: Output 'Index ', followed by the element's index, ': ', and the element's value. Increase sum_passed by each such element's value. # Read input and split input into tokenstokens = input().split() pressure_data = []for token in tokens: pressure_data.append(int(token)) print(f'All data: {pressure_data}') ''' Your code goes here ''' print(f'Sum of selected elements is: {sum_passed}')
In python 3 We all know that when the temperature of a metal increases, it begins to expand. So,we experimented with exposing a metal rod to different temperatures and recorded itslength as follows:Temp 20 25 30 35 40 45 50 55 60 65Length 0.5 1.8 5 6 6.2 6.5 7.8 9.4 9.8 10.9 Now do these requirments: 1) Implement and plot a simple linear regression for the above data, where the temperature is “x”, and the length is “y” 2) Implement and plot a multiple linear regression "Polynomial regression" with different degrees.For example, Degree of 3:Y = w1x1 + w2x2 + w3x3 + w4Where w4 represents bias.*you can use a normal equation to calculate ‘W’ as follow:W = (XT.X)-1.(XT.Y)Then calculate Y, Where Y = X.WT 3) Try degrees of 2, 3, 5, and 8
Write Algorithm for Linear congruential method for generating random integer numbers within the interval [0, m) out: random integer r (0 ≤ r ≤ m − 1)constant: modulus m; multiplier a; increment c; starting value X0 (1 ≤ m ∧ 0 ≤a, c, X0 ≤ m − 1 ∧ (m mod a) ≤ m/a)local: previously generated random number x (initially x = X0) don't reject if you don't know answer it's complete question
For the following code, match the outcome if x = The answers I got were wrong
Using Java create a computer program that will perform any or a combination of numerical methods y. For example, a program that do regression analysis, outputs a linear model and determine the correlation.
What are all possible results of the expression (n % m), where n and m are positive integer variables?
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Create a random number generation algorithm using a distribution represented by a finite series of weights.(Wi N for I = 0,... (n 1) 1 n1 i=0 Wi) sequence of n weights W representing the distributionout: Index r was chosen at random in accordance with W (0 r m 1)
Your friend is interested in generating a bootstrap sample from some original sample by sampling its observation indices. But you observe that he types sample(n,n,replace=TRUE) in R (where n is the original sample size). You argue that he should type sample(n,n,replace=FALSE) instead. Who is correct? Both operations are acceptable and give the desired result. The replace input argument here is redundant and would only matter if we are carrying out cross-validation. You are both wrong. You need to use more information in order to be able to generate a legitimate sample. You are right. The sampling has to be done without replacement. Your friend is right. Sampling without replacement will give identical estimates with respect to the original sample.