Exercise 1.4.9 (Challenging): A number x is algebraic if x is a root of a polynomial with integer coefficients, in other words, anx"+an_₁x²¹+...+a₁x+ao=0 where all an € Z. a) Show that there are only countably many algebraic numbers. b) Show that there exist non-algebraic (transcendental) numbers (follow in the footsteps of Cantor, use the uncountability of R).
Exercise 1.4.9 (Challenging): A number x is algebraic if x is a root of a polynomial with integer coefficients, in other words, anx"+an_₁x²¹+...+a₁x+ao=0 where all an € Z. a) Show that there are only countably many algebraic numbers. b) Show that there exist non-algebraic (transcendental) numbers (follow in the footsteps of Cantor, use the uncountability of R).
Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter8: Polynomials
Section8.2: Divisibility And Greatest Common Divisor
Problem 35E
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Question
Please solve all parts of exercise 1.4.9 with detailed explanations. Take your time.
Expert Solution
Step 1
A number is said to be algebraic number of is a root of a polynomial with integer coefficients.
In other words, , where all .
In this solution we will prove that there are only countably many algebraic numbers.
Also we will prove that there exists non algebraic numbers.
In this solution, we will use the fact that has finitely many positive integer solution for all .
Also we will use the fact that countable union of countable sets is countable.
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