Exercise 3.28. It is obvious that if T1 is both coarser and finer than T2 on X, then the topologies are equal (we say the topologies on X are equivalent). Prove it anyway. Then give a reason why we might have chosen the "coarser/finer" language.

Algebra & Trigonometry with Analytic Geometry
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ISBN:9781133382119
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Chapter10: Sequences, Series, And Probability
Section10.7: Distinguishable Permutations And Combinations
Problem 30E
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Solve Exercise 3.28

Definition 3.27. Let X be a set and T1 and T2 be topologies on X. If T1 C T2, we say
that Ti is coarser than T2 and that T2 is finer than T1. If T1 C Tz and T1 # T2, we say that
Ti is strictly coarser than T2 and that T2 is strictly finer than T1.
Exercise 3.28. It is obvious that if T1 is both coarser and finer than T2 on X, then the
topologies are equal (we say the topologies on X are equivalent). Prove it anyway. Then
give a reason why we might have chosen the "coarser/finer" language.
Transcribed Image Text:Definition 3.27. Let X be a set and T1 and T2 be topologies on X. If T1 C T2, we say that Ti is coarser than T2 and that T2 is finer than T1. If T1 C Tz and T1 # T2, we say that Ti is strictly coarser than T2 and that T2 is strictly finer than T1. Exercise 3.28. It is obvious that if T1 is both coarser and finer than T2 on X, then the topologies are equal (we say the topologies on X are equivalent). Prove it anyway. Then give a reason why we might have chosen the "coarser/finer" language.
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