Exercise 5.1.14. Suppose G is an abelian group. Show {g E G : g² = e} is a subgroup of G. Give an explicit counterexample to show this is not necessarily true when G is not abelian.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
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Chapter4: More On Groups
Section4.6: Quotient Groups
Problem 31E: 31. (See Exercise 30.) Prove that if and are primes and is a nonabelian group of order , then the...
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Exercise 5.1.14. Suppose G is an abelian group. Show {g E G : g² = e} is a subgroup of G. Give an
explicit counterexample to show this is not necessarily true when G is not abelian.
%3D
Transcribed Image Text:Exercise 5.1.14. Suppose G is an abelian group. Show {g E G : g² = e} is a subgroup of G. Give an explicit counterexample to show this is not necessarily true when G is not abelian. %3D
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