Question
Asked Oct 8, 2019
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Exercise:
A sinewave voltage with amplitude 2 V and frequency 500 Hz is applied across an
ideal inductor. The inductance is 500 mH. What is the amplitude of the current?
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Exercise: A sinewave voltage with amplitude 2 V and frequency 500 Hz is applied across an ideal inductor. The inductance is 500 mH. What is the amplitude of the current?

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Expert Answer

Step 1

Drawing the circuit by using the given data from question:

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i 2sin1000 500MH f =500HZ

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Step 2

The value of angular frequency (ω) is given as:

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27f 27(500) =10007

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Step 3

It is given that, the inductor is ideal in nature, which mea...

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R=O

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Electrical Engineering

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