Exercise (b) the centroid of the region bounded by the graphs of the equations Step 1 The region is bounded by the graphs of the equations y = sin x, y = 0, x = 0, and x = x. y=sin(x) b $ ax The area of the representative rectangle is dA = (sin x So, the area of the entire region is A = For the above region, f(x)=sin x g(x) = 0 a = 0,b= Therefore, Let Use integration by parts. Let u= -cos x Step 2 The x-coordinate of the centroid for a region of constant density is x=x[rx) - 9(x)] dx. V= Using integration by parts Therefore, Sudv=uv - [vdu. Differentiate with respect to x on both sides. du - dx * - ** x= ✓ dv = sin x dx. Integrate with respect to x on both sides. x sin x dx --x テー ✓ sin (r) dx. -x cos x + Isin x dx -cos(r) 2 2 -[-x cos x + * cos x dx] x sin x dx. 1] The x-coordinate of the centroid of the region is

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Exercise (b)
the centroid of the region bounded by the graphs of the equations
Step 1
The region is bounded by the graphs of the equations
y sin x, y = 0, x = 0, and xx.
The area of the representative rectangle is
dA= (sin x
So, the area of the entire region is
A =
=
Therefore,
Let
Let
For the above region,
f(x) = sin x
g(x) = 0
a = 0,b=
y=sin(x)
K
U=
2
Use integration by parts.
Step 2
The x-coordinate of the centroid for a region of constant density is
x = = ®x[f(x) - g(x)] d
dx.
-cos x
V =
-1
Therefore,
Differentiate with respect to x on both sides.
du = dx
Using integration by parts
Ju dv = uv- -/₁
dv sin x dx.
Integrate with respect to x on both sides.
x=
1
* = = 6*²*
x
-1/[x²
x sin x dx
v du.
sin (r)) dx.
✓sin x dx
-x cos x +
2
- cos (r)
+6²°
-x cos x +
x sin x dx.
- 1/21 - x0
The x-coordinate of the centroid of the region is
1
cos x dx
10
Transcribed Image Text:Exercise (b) the centroid of the region bounded by the graphs of the equations Step 1 The region is bounded by the graphs of the equations y sin x, y = 0, x = 0, and xx. The area of the representative rectangle is dA= (sin x So, the area of the entire region is A = = Therefore, Let Let For the above region, f(x) = sin x g(x) = 0 a = 0,b= y=sin(x) K U= 2 Use integration by parts. Step 2 The x-coordinate of the centroid for a region of constant density is x = = ®x[f(x) - g(x)] d dx. -cos x V = -1 Therefore, Differentiate with respect to x on both sides. du = dx Using integration by parts Ju dv = uv- -/₁ dv sin x dx. Integrate with respect to x on both sides. x= 1 * = = 6*²* x -1/[x² x sin x dx v du. sin (r)) dx. ✓sin x dx -x cos x + 2 - cos (r) +6²° -x cos x + x sin x dx. - 1/21 - x0 The x-coordinate of the centroid of the region is 1 cos x dx 10
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