Exercise: Separate the variables and solve. 1. x(2y-3)dx+(x²+1)dy=0 ans: (x²+1)(2y-3)=Fc

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Exercise: Separate the variables and solve.
1. x(2y-3)dx+(x²+1)dy=0
ans: (x*+1)(2y-3)=c
2. dy=e* dx
ans: e'=e*+c
dy
3. sin x
+cosh 2y=0
dx
ans: sinh 2y-2cosx=c
x² +1
4. xe'dy+:
ans: e'(y-1)+ +In |x|=c
2
dx = 0
y
1
dy
5. 2xy -
= 1
ans:
= x? +c
dx
Transcribed Image Text:Exercise: Separate the variables and solve. 1. x(2y-3)dx+(x²+1)dy=0 ans: (x*+1)(2y-3)=c 2. dy=e* dx ans: e'=e*+c dy 3. sin x +cosh 2y=0 dx ans: sinh 2y-2cosx=c x² +1 4. xe'dy+: ans: e'(y-1)+ +In |x|=c 2 dx = 0 y 1 dy 5. 2xy - = 1 ans: = x? +c dx
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