Exercise. The position vector for a particle is described by the vector-valued function: sin(at) r(t) = cos(at), for t > 0. Find (positive) a so the curve uses arc length as a parameter. Exercise. Let C be a curve drawn by: r(t) = (sin(t) – 1, 2 sin(t) + 2, –2 sin(t)) Find the length of the curve drawn by r ast runs from -T/2 to T/2: length

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.4: Plane Curves And Parametric Equations
Problem 33E
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Exercise. The position vector for a particle is described by the vector-valued function:
sin(at)
r(t) =
cos(at),
for t > 0. Find (positive) a so the curve uses arc length as a parameter.
Transcribed Image Text:Exercise. The position vector for a particle is described by the vector-valued function: sin(at) r(t) = cos(at), for t > 0. Find (positive) a so the curve uses arc length as a parameter.
Exercise. Let C be a curve drawn by:
r(t) = (sin(t) – 1, 2 sin(t) + 2, –2 sin(t))
Find the length of the curve drawn by r ast runs from -T/2 to T/2:
length
Transcribed Image Text:Exercise. Let C be a curve drawn by: r(t) = (sin(t) – 1, 2 sin(t) + 2, –2 sin(t)) Find the length of the curve drawn by r ast runs from -T/2 to T/2: length
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