# Exercises: # • Modify the machine to check if n-1 is divisible by 3, where n is the input. That is, accept the binary of 1, 4, 7, 10, 23 %23 Hint: this can be done without modifying the tape (no 'write'). - # • Round the number up to the nearest multiple of 3. Hint: do one pass right to find the remainder, then another pass #3 left

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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Turing machine Algorithm. please answer the question under the exercise part and the bottom fully and everything.

1 # Checks if a binary number is divisible by 3.
2 input: '10011' # try '1111' (15), '10100' (20), '111001' (57)
3 blank: .
# How it works:
4
6- # Consider neading a binary number, say 10011 (19),
# from left to right one digit at a time.
8.
7
# Each time a digit is read, the new value equals the new digit
9.
# plus the old value shifted left one place (multiplied by 2).
10
11 - # Digits Value
12
23
13
14
15
#3
# 1
# 10
16
# 100
4
# 1001
18
17
# 10011
19
19
20 - # Now instead of tracking the entire number, just track the remainder.
21
# It works the same way.
22
start state: q0
23 - table:
24-
q0:
0: R
1: {R: q1} # 2*0 + 1 = 1
# 2*0 + 0 -0
25
26
27
: {R: accept}
28 -
29
30
q1:
0: {R: q2} # 2*1 + 0 = 2
1: {R: q0} # 2*1 + 1 - 3
q2:
0: {R: q1} # 2*2 + 0 =4
1: {R: q2} # 2*2 + 1 =5
ассеpt:
31-
32
33
34
35
36
# Exercises:
38
39 - # • Modify the machine to check if n-1 is divisible by 3,
#3
37
40
where n is the input. That is, accept the binary of 1, 4, 7, 10,
...
41
Hint: this can be done without modifying the tape (no 'write').
2#3
42
43 - # • Round the number up to the nearest multiple of 3.
#3
Hint: do one pass right to find the remainder, then another pass
left
44
Transcribed Image Text:1 # Checks if a binary number is divisible by 3. 2 input: '10011' # try '1111' (15), '10100' (20), '111001' (57) 3 blank: . # How it works: 4 6- # Consider neading a binary number, say 10011 (19), # from left to right one digit at a time. 8. 7 # Each time a digit is read, the new value equals the new digit 9. # plus the old value shifted left one place (multiplied by 2). 10 11 - # Digits Value 12 23 13 14 15 #3 # 1 # 10 16 # 100 4 # 1001 18 17 # 10011 19 19 20 - # Now instead of tracking the entire number, just track the remainder. 21 # It works the same way. 22 start state: q0 23 - table: 24- q0: 0: R 1: {R: q1} # 2*0 + 1 = 1 # 2*0 + 0 -0 25 26 27 : {R: accept} 28 - 29 30 q1: 0: {R: q2} # 2*1 + 0 = 2 1: {R: q0} # 2*1 + 1 - 3 q2: 0: {R: q1} # 2*2 + 0 =4 1: {R: q2} # 2*2 + 1 =5 ассеpt: 31- 32 33 34 35 36 # Exercises: 38 39 - # • Modify the machine to check if n-1 is divisible by 3, #3 37 40 where n is the input. That is, accept the binary of 1, 4, 7, 10, ... 41 Hint: this can be done without modifying the tape (no 'write'). 2#3 42 43 - # • Round the number up to the nearest multiple of 3. #3 Hint: do one pass right to find the remainder, then another pass left 44
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