Answered: Existence of a Zero In Exercises 83–88,…

Existence of a Zero In Exercises 83–88, explain why the function has at least one zero in the given interval. Function Interval 83. f(x) = px4 – x³ + 4 [1, 2] %3D 12 87. h(x) = - 2e-x/2 cos 2x 2

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter5: Inverse, Exponential, And Logarithmic Functions

Section5.3: The Natural Exponential Function

Problem 50E

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Question

explain why the function has at least 1 zero in the interval

this is a calculus problem

there are 2 problems involving the explanation on why there might be at least 1 zero to the orignal equations list ona separate attachment

Existence of a Zero In Exercises 83-88, explain why the
function has at least one zero in the given interval.
Function
Interval
83. f(x) = px4 – x³ + 4
[1, 2]
12-t
87. h(x) = - 2e-/2 cos 2x
%3D

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