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Experiments show that a colony of bacteria with sufficient food and no predators and with zero death rate, grows at a rate proportional to the size of the its population P at time t (in minutes). Hence the population P satisfies the initial value problem dP -=kP, or some positive constant k (in/minute) where the initial population P(0) = P = 27411.08 bacteria (decimals allowed). If dt 0 the population doubled after 23.41 minutes, when will the population triple? Answer: minutes. (Use two decimal places for the answer, no units needed)

Experiments show that a colony of bacteria with sufficient food and no predators and with zero death rate, grows at a rate proportional to the size of the its population P at time t (in minutes). Hence the population P satisfies the initial value problem dP -=kP, or some positive constant k (in/minute) where the initial population P(0) = P = 27411.08 bacteria (decimals allowed). If dt 0 the population doubled after 23.41 minutes, when will the population triple? Answer: minutes. (Use two decimal places for the answer, no units needed)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 9T
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Experiments show that a colony of bacteria with sufficient food and no predators and with zero death rate, grows at a rate proportional to the size of the its population P at time t (in minutes). Hence the population P satisfies the initial value problem dP -=kP, or some positive constant k (in /minute) where the initial population P(0) = P = 27411.08 bacteria (decimals allowed). If dt 0 the population doubled after 23.41 minutes, when will the population triple? minutes. (Use two decimal places for the answer, no units needed) Answer:
Transcribed Image Text:Experiments show that a colony of bacteria with sufficient food and no predators and with zero death rate, grows at a rate proportional to the size of the its population P at time t (in minutes). Hence the population P satisfies the initial value problem dP -=kP, or some positive constant k (in /minute) where the initial population P(0) = P = 27411.08 bacteria (decimals allowed). If dt 0 the population doubled after 23.41 minutes, when will the population triple? minutes. (Use two decimal places for the answer, no units needed) Answer:
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