Explain the functionality of below recursive functions. static void fun1(int n) { int i = 0; if (n > 1) fun1(n - 1); for (i = 0; iLIMIT)return; System.out.print( String.format("%d", n)); fun2(2*n); System.out.print( String.format("%d", n)) }
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Explain the functionality of below recursive functions.
static void fun1(int n)
{
int i = 0; if (n > 1)
fun1(n - 1); for (i = 0; i<n; i++)
System.out.print(" *");
}
2.
int LIMIT = 1000;
void fun2(int n)
{
if (n<=0)return;
if (n>LIMIT)return;
System.out.print(
String.format("%d",
n));
fun2(2*n);
System.out.print(
String.format("%d",
n))
}
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- (Using the programming language C, answer the following question) Write recursive C functions to do the following: Example: int summ(int n) returns the summation of integers from 0 to n. Here is the code. int summ(int n) { if(n < 0) return -1; if(n == 0) return 0; return n + summ(n - 1);} 1) If n is less than 0, the expression int bunnyEars(int n) returns -1; otherwise, it returns the number of ears for n bunnies. int factorial(int n) returns -1 if n is less than 0, otherwise returns the factorial of n. If n is greater than or equal to 0, the expression int fib(int n) returns -1; otherwise, it returns fib of n - 1 + fib of n - 2. (This will run quite slowly if you test it with more than roughly 50 digits.). int posPow(int base, int exp) returns -1 if exp is less than 0, otherwise returns base raised to the power exp. Write a main() that tests all the other functions thoroughly.Write a recursive function that returns true if the digits of a positive integer are in increasing order; otherwise, the function returns false. Also, write a program to test your function.Which is the base case of the following recursion function: def mult3(n): if n == 1: return 3 else: return mult3(n-1) + 3 else n == 1 mult3(n) return mult3(n-1) + 3
- For function addOdd(n) write the missing recursive call. This function should return the sum of all postive odd numbers less than or equal to n. Examples: addOdd(1) -> 1addOdd(2) -> 1addOdd(3) -> 4addOdd(7) -> 16 public int addOdd(int n) { if (n <= 0) { return 0; } if (n % 2 != 0) { // Odd value return <<Missing a Recursive call>> } else { // Even value return addOdd(n - 1); }}Consider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?Implement a recursive C++ function which takes a character (ch) and a positive integer (n) and prints thecharacter ch, n times on the screen. The prototype of your function should be:void printChar (char ch, int n)For example, calling printChar('*',5) should display ***** on screen.Note: There should NOT be any loop in your function.
- Write a recursive fibonacci (n) function with an expression body. The function should return an Int; it will be too slow to deal with inputs whose fibonacci numbers are too large anyway. You do *not* need to use memoization. Note that: fibonacci(0) = 0 fibonacci(1) = 1 fibonacci(n, where n is greater than 1) = fibonacci(n-2) + fibonacci(n - 1)Consider the recursive procedure which computes the nth Fibonacci number is the one below. procedure Fl (n) //a function which returns the nth Fibonacci number.// if n < 2 then return(n) else return (F2(2,n,1,1)) endif end Fl procedure F2(i,n,x,y) if iThe Polish mathematician Wacław Sierpiński described the pattern in 1915, but it has appeared in Italian art since the 13th century. Though the Sierpinski triangle looks complex, it can be generated with a short recursive function. Your main task is to write a recursive function sierpinski() that plots a Sierpinski triangle of order n to standard drawing. Think recursively: sierpinski() should draw one filled equilateral triangle (pointed downwards) and then call itself recursively three times (with an appropriate stopping condition). It should draw 1 filled triangle for n = 1; 4 filled triangles for n = 2; and 13 filled triangles for n = 3; and so forth. API specification. When writing your program, exercise modular design by organizing it into four functions, as specified in the following API: public class Sierpinski { // Height of an equilateral triangle whose sides are of the specified length. public static double height(double length) // Draws a filled equilateral…
- Need some help with this c++ problem In order to compute a power of two, you can take the next-lower power and double it. For example, if you want to compute 211 and you know that 210 = 1024, then 211 = 2 × 1024 = 2048. Based on this observation, write a recursive function int pow2(int n) where n is the exponent. If the exponent is negative, return -1. int pow2(int n) { ..... }Given the recursive function definition:t(n) = n+ 3 * t(n-1) + t(n-2) t(0) = 2 t(1) = 1a. Evaluate: t(3)b. Write the source code to implement this functionWrite a recursive function in Java that accepts an integer as input and returns 1 + 1/2 + 3 + 1/4 + ...(n or 1/n). The answer is the sum of the odd integers from 1 to n plus the sum of the reciprocals of the even integers.