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Explain what it means to say that lim f(x) = 3 and X 6 X→ 6+ O As x approaches 6, f(x) approaches 5, but f(6) = 3. As x approaches 6, f(x) approaches 3, but f(6) = 5. As x approaches 6 from the right, f(x) approaches 3. As x approaches 6 from the left, f(x) approaches 5. As x approaches 6 from the left, f(x) approaches 3. As x approaches 6 from the right, f(x) approaches 5. lim f(x) = 5. In this situation is it possible that lim f(x) exists? Explain. X-6 O Yes, f(x) could have a hole at (6, 3) and be defined such that f(6) = 5. O Yes, f(x) could have a hole at (6, 5) and be defined such that f(6) = 3. Yes, if f(x) has a vertical asymptote at x = 6, it can be defined such that lim f(x) = 3, lim f(x) = 5, and lim f(x) exist X-6 X→6+ X-6 No, lim f(x) cannot exist if lim_ f(x) # lim f(x). x 6 X-6- x→6+

Explain what it means to say that lim f(x) = 3 and X 6 X→ 6+ O As x approaches 6, f(x) approaches 5, but f(6) = 3. As x approaches 6, f(x) approaches 3, but f(6) = 5. As x approaches 6 from the right, f(x) approaches 3. As x approaches 6 from the left, f(x) approaches 5. As x approaches 6 from the left, f(x) approaches 3. As x approaches 6 from the right, f(x) approaches 5. lim f(x) = 5. In this situation is it possible that lim f(x) exists? Explain. X-6 O Yes, f(x) could have a hole at (6, 3) and be defined such that f(6) = 5. O Yes, f(x) could have a hole at (6, 5) and be defined such that f(6) = 3. Yes, if f(x) has a vertical asymptote at x = 6, it can be defined such that lim f(x) = 3, lim f(x) = 5, and lim f(x) exist X-6 X→6+ X-6 No, lim f(x) cannot exist if lim_ f(x) # lim f(x). x 6 X-6- x→6+

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Explain what it means to say that lim f(x) = 3 and lim f(x) = 5. X→6- x+6+ O As x approaches 6, f(x) approaches 5, but f(6) = 3. O As x approaches 6, f(x) approaches 3, but f(6) = 5. O As x approaches 6 from the right, f(x) approaches 3. As x approaches 6 from the left, f(x) approaches 5. As x approaches 6 from the left, f(x) approaches 3. As x approaches 6 from the right, f(x) approaches 5. In this situation is it possible that lim f(x) exists? Explain. X→ 6 Yes, f(x) could have a hole at (6, 3) and be defined such that f(6) = 5. O Yes, f(x) could have a hole at (6, 5) and be defined such that f(6) = 3. O Yes, if f(x) has a vertical asymptote at x = 6, it can be defined such that lim f(x) = 3, lim f(x) = 5, and lim f(x) exist X→6- X→6+ X-6 O No, lim f(x) cannot exist if lim_ f(x) # lim f(x). x 6 X→6- X→6+
Transcribed Image Text:Explain what it means to say that lim f(x) = 3 and lim f(x) = 5. X→6- x+6+ O As x approaches 6, f(x) approaches 5, but f(6) = 3. O As x approaches 6, f(x) approaches 3, but f(6) = 5. O As x approaches 6 from the right, f(x) approaches 3. As x approaches 6 from the left, f(x) approaches 5. As x approaches 6 from the left, f(x) approaches 3. As x approaches 6 from the right, f(x) approaches 5. In this situation is it possible that lim f(x) exists? Explain. X→ 6 Yes, f(x) could have a hole at (6, 3) and be defined such that f(6) = 5. O Yes, f(x) could have a hole at (6, 5) and be defined such that f(6) = 3. O Yes, if f(x) has a vertical asymptote at x = 6, it can be defined such that lim f(x) = 3, lim f(x) = 5, and lim f(x) exist X→6- X→6+ X-6 O No, lim f(x) cannot exist if lim_ f(x) # lim f(x). x 6 X→6- X→6+
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