Explain why the function is differentiable at the given point f(x, y) - y + sin (0, 8) The partial derivatives are f (x, y) = and f,(x, y) = , so f (0, 8) =| and f,(0, 8) | Both f and f, are continuous functions forSelectv is differentiable at (0, 8). Find the linearization L(x, y) of the function at (0, 8). L(x, y) =|

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Explain why the function is differentiable at the given point.
(주)
f(x, y) - y + sin
(0, 8)
The partial derivatives are f (x, y) =
and f,(x, y) =
, so f (0, 8) = |
and f,(0, 8) |
Both f and f, are continuous functions for Selectv
is differentiable at (0, 8).
Find the linearization L(x, y) of the function at (0, 8).
L(x, y) =|
Explain why the function is differentiable at the given point.
(x, y) x°e, (1, 0)
and f,(x, y) =
,so f,(1, 0)-
and f,(1, 0)-|
Both and f are continuous functions, so f is differentiable at
The partial derivatives are f (x, y) =
(1, 0).
Find the linearization L(x, y) of the function at (1, 0)
L(x, y) =
Transcribed Image Text:Explain why the function is differentiable at the given point. (주) f(x, y) - y + sin (0, 8) The partial derivatives are f (x, y) = and f,(x, y) = , so f (0, 8) = | and f,(0, 8) | Both f and f, are continuous functions for Selectv is differentiable at (0, 8). Find the linearization L(x, y) of the function at (0, 8). L(x, y) =| Explain why the function is differentiable at the given point. (x, y) x°e, (1, 0) and f,(x, y) = ,so f,(1, 0)- and f,(1, 0)-| Both and f are continuous functions, so f is differentiable at The partial derivatives are f (x, y) = (1, 0). Find the linearization L(x, y) of the function at (1, 0) L(x, y) =
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