Express the confidence interval (78,98)(78,98) in the form of ¯x±MEx¯±ME. ¯x±ME=x¯±ME= ±±
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Express the confidence interval (78,98)(78,98) in the form of ¯x±MEx¯±ME.
¯x±ME=x¯±ME= ±±
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- A random sample of 50 ladybirds of a particular species is collected, and the length of each ladybird measured to the nearest millimetre, giving a sample mean of 6.5 millimetres, and a sample standard deviation of 2 millimetres. Find an 99% confidence interval for the population mean length of ladybirds of this species, giving each limit in millimetres to 2 decimal places.A simple random sample from a population with a normal distribution of 104 body temperatures has x=98.70°F and s=0.62°F. Construct a 90% confidence interval estimate of the standard deviation of body temperature of all healthy humans. Is it safe to conclude that the population standard deviation is less than 0.80°F?Records of the past 15 years have shown the average revenue of company A for the month of March to be 5.05M pesos, with a population standard deviation of 1.64M. Company B has had an average revenue in March of 3.78M during the past 10 years with a population standard deviation of 0.92M. Find a 95% confidence interval for the difference of the true revenues in these two companies, assuming the observations come from normal populations.
- A statistics student randomly selected 45 packets of sugar and weighed the contents of each packet, getting a mean of 3.586 grams and a standard deviation of 0.194 grams. Test the claim that the weights of the sugar packets have a mean no longer equal to 3.5 grams, as indicated on the label. Let "alpha" be 0.10 to test this claim. What are the hypotheses to be tested?The mean height for a sample of n = 81 women is x = 63.5 inches, and the standard deviation is s = 3.6 inches. Find the standard error of the mean (in inches). in Find an approximate 95% confidence interval for the population mean (in inches), using the approximation that is appropriate for large samples. to inA sample obtained from a population with σ = 12 has a standard error of σx̅ = 2 points. How many scores are in the sample?
- A random sample of 5 months in an urban area showed an average of 28 mail carriers were bitten by dogs. If the population is normal and the standard deviation of the sample is 3, find the 95% confidence interval for the population mean.A statistical study is made to compare the % of smokers in small rural towns to the overall smoking rate of the US. Of 1500 asults selected randomly from small towns it is found that 285 of them smoke. Construct a 95% cofidence interval for the true % of all adults in small towns that smoke.A simple random sample from a population with a normal distribution of 109 body temperatures has x=98.30∘F, and s=69∘F. Construct a 99% confidence interval estimate of the standard deviation of body temperature of all healthy humans. __F <ó<__F Round to two decimal places as needed.
- a consumer analyst reports that the mean life of a certain type of alkaline battery is no more than 63 months. write the null and alternative hypotheses and ote which is the claimA random sample of 46 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.01 years, with sample standard deviation s = 0.72 years. However, it is thought that the overall population mean age of coyotes is μ = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use α = 0.01. State the null and alternate hypotheses. H0: μ < 1.75 yr; H1: μ = 1.75 yr H0: μ > 1.75 yr; H1: μ = 1.75 yr H0: μ = 1.75 yr; H1: μ ≠ 1.75 yr H0: μ = 1.75 yr; H1: μ > 1.75 yr H0: μ = 1.75 yr; H1: μ < 1.75 yr (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. The standard normal, since the sample size is large and σ is known. The Student's t, since the sample size is large and σ is unknown. The standard normal, since the sample size is large and σ is unknown. The Student's t, since the sample size is large and σ is known. What…A simple random sample from a population with a normal distribution of98body temperatures has x=98.40°F and s=0.68°F. Construct an 80%confidence interval estimate of the standard deviation of body temperature of all healthy humans.